4.2 volts across 50 ohms is +25 dBm. 0.5 uV across 50 ohms is -113 dBm. That's an awful lot of attenuation you're going to need (25 + 113)--I doubt your extensive shielding needed between input and output will be sufficient.
Steve AA7U
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On 3/23/2025 8:20 AM, chuck adams via groups.io wrote:
I did the math.? Fundamental amplitude for a square wave is 4*A/pi, where A is the square
wave amplitude.? For A=3.3V, then fundamental is 4*3.3/pi ~= 4.2V.? Just attenuate to
0.5uV and let the receiver remove all the harmonics.? I think this will work and we
won't have to switch between filters in the generator.? Someone do the experiment
and report back.
I'm 532/937 on ProjectEuler.net, so I think my math is right.
