开云体育

S9 generator

chuck adams All Messages By This Member #8989 I did the math.? Fundamental amplitude for a square wave is 4A/pi, where A is the square wave amplitude.? For A=3.3V, then fundamental is 43.3/pi ~= 4.2V.? Just attenuate to 0.5uV and let the receiver remove all the harmonics.? I think this will work and we won't have to switch between filters in the generator.? Someone do the experiment and report back. I'm 532/937 on ProjectEuler.net, so I think my math is right.
Steve Ratzlaff All Messages By This Member #8991 4.2 volts across 50 ohms is +25 dBm. 0.5 uV across 50 ohms is -113 dBm. That's an awful lot of attenuation you're going to need (25 + 113)--I doubt your extensive shielding needed between input and output will be sufficient. Steve AA7U toggle quoted message Show quoted text On 3/23/2025 8:20 AM, chuck adams via groups.io wrote: I did the math.? Fundamental amplitude for a square wave is 4A/pi, where A is the square wave amplitude.? For A=3.3V, then fundamental is 43.3/pi ~= 4.2V.? Just attenuate to 0.5uV and let the receiver remove all the harmonics.? I think this will work and we won't have to switch between filters in the generator.? Someone do the experiment and report back. I'm 532/937 on ProjectEuler.net, so I think my math is right.
Don VE3IDS All Messages By This Member #8992 I believe you can reduce the output level somewhat in the software to help with the attenuation.? 73 Don ve3ids? toggle quoted message Show quoted text On Sun., Mar. 23, 2025, 11:38 a.m. Steve Ratzlaff via , <ratzlaffsteve=[email protected]> wrote: 4.2 volts across 50 ohms is +25 dBm. 0.5 uV across 50 ohms is -113 dBm. That's an awful lot of attenuation you're going to need (25 + 113)--I doubt your extensive shielding needed between input and output will be sufficient. Steve AA7U On 3/23/2025 8:20 AM, chuck adams via wrote: > I did the math.? Fundamental amplitude for a square wave is 4A/pi, > where A is the square > wave amplitude.? For A=3.3V, then fundamental is 43.3/pi ~= 4.2V.? > Just attenuate to > 0.5uV and let the receiver remove all the harmonics.? I think this > will work and we > won't have to switch between filters in the generator.? Someone do the > experiment > and report back. > > I'm 532/937 on ProjectEuler.net, so I think my math is right. > > > > >
Steve Ratzlaff All Messages By This Member #8995 Before 40 people jump in to correct me on absolute levels from this square wave output, I was being somewhat tongue in cheek in my reply. Even if the absolute fundamental output of this generator is even 0 dBm, there is a lot of attenuation needed to get the signal down to -113 dBm. (It's easier to think in dB units than volts.) 73, Steve AA7U toggle quoted message Show quoted text On 3/23/2025 8:38 AM, Steve Ratzlaff wrote: 4.2 volts across 50 ohms is +25 dBm. 0.5 uV across 50 ohms is -113 dBm. That's an awful lot of attenuation you're going to need (25 + 113)--I doubt your extensive shielding needed between input and output will be sufficient. Steve AA7U On 3/23/2025 8:20 AM, chuck adams via groups.io wrote: I did the math.? Fundamental amplitude for a square wave is 4A/pi, where A is the square wave amplitude.? For A=3.3V, then fundamental is 43.3/pi ~= 4.2V.? Just attenuate to 0.5uV and let the receiver remove all the harmonics.? I think this will work and we won't have to switch between filters in the generator.? Someone do the experiment and report back. I'm 532/937 on ProjectEuler.net, so I think my math is right.
parad0x All Messages By This Member #8996 On Sun, Mar 23, 2025 at 04:20 PM, chuck adams wrote: ? Just attenuate to 0.5uV and let the receiver remove all the harmonics. ? The title says S9 (50uV) generator. What are the 0.5uV for? ? -- 73, Robert

Previous Topic Next Topic