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If you used this BNC to Banana adapter, you are adding about 2 pF or so of shunt capacitance across the feed point of your test dipole. At 500 MHz for example, this is about Xc = 159 ohms. This

This is the part of LF model that don’t work basically because is the wrong frequency region…

Hi Patricio Thanks for clarification , I do not understand this graphic zone circled on red color below 73's Nizar

This chart shows the typical behaviour of a loosy coaxial cable over frequency. Basically there are two models , the low frequency model in this case the dielectric loose are very small then G tends

Hi With same coax, same method, same NanoVNA H4 (1.2.40 DiSlord) surprisingly i have some different Zc values for 50Mhz & 100Mhz 50Mhz ---> Zc = 49.0 Ohm 100Mhz ---> Zc = 43.5 Ohm 73's Nizar

Hi Patricio I do not understand this chart, can you explaine it more pse. 73's Nizar

Oops! I should have R >> jwL, not R >> jwC. My error. 73, Maynard W6PAP

An interesting chart. Note that below about 300 kHz, the imaginary component of the characteristic impedance can no longer be ignored and, if you are working on any cables at voice frequencies or

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Hi Jim Lux "L , C & R exhibit some frequency-dependent variation; they do not have a perfectly flat response across frequency. This behavior depends on the dielectric material used, skin effect

Not unexpected Zc is sqrt( (R+jomegaL)/(G+jomegaC)) Mostly determined by L/C, but the R is in there too, and it goes up as frequency goes up, because of skin effect. For HF the dielectric loss (G) is

Interesting , the Zo uses to rise a little when the frequency goes down.

Hi for same RG213 cable (25m length) loaded by a 50.3 Ohm resistor I used the same circle methode centered on smith graph with the renormalized Z0 impedance ( option added by DiSlord) for

Hi Dave DiSlord coax function seems using Zc = 1/(4*fr*C0) , fr= is the first resonance frequency with open terminaison it's around 1.7Mhz measured by NANoVNA. C0 = capacitance value at lower

I wonder how the "short / open" method compares using Zc = SQRT [L / C] ? Of course, that will introduce losses due to theoretical infinite SWR. Dave - W?LEV [email protected]> wrote:

Hi I think that this method of small circles centered with the renormalized impedance at the center of the Smith graph, must bring two advantages compared to that used by the DiSlord method: 1) we

Hi below what i have measured on smith graph with my 25m length of RG213 coax cable with a NanoVNA H4 With Dislord function and no terminaison : it gives Z0=51.7 Ohm , it do not change with

I have this problem even with my recently purchased NanoVNA. Sometimes when I switch on, the screen is blank. If I switch off and switch on once again, usually it becomes OK. The problem recurs again

John, Thank you for your advice; I think that is the reason for the fault. I tried that and operated the unit outside of the case and it seemed to work a little better but the menu still flickered

William, Also check for battery swelling causing pressure on the display. --John Gord