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I think everyone is trying to work towards the same goal here, and I
am very thankful for everyone providing their valuable expertise here.
I don't think anyone is trying to dispute that Mr. F1EKU is the expert
here, the rest of us have only theoretical or synthetic/lab experience
compared to him, if at all!

F1EKU thank you very much for bringing up the fact that a partial
discharge is happening. That's interesting in and of itself.

My current measurements are only limited to getting shocked
repeatedly. Can one extrapolate the rough voltage from the pain scale?
e.g. what potential differential might one be dealing with if touching
a rack makes you scream out?

One comment was mentioned earlier that a neon bulb would only activate
for a short time when dealing with ESD due to the low charge applied.
Would a photoresistor + hold circuit combination be able to capture
the minuscule light that comes off the neon bulb, or does the neon
need higher voltage to activate in the first place?

Thank you everyone for replying and continued commentary

On Wed, May 22, 2024 at 6:04?PM ed breya via groups.io
<eb@...> wrote:

I used 27 kV to get the most out that I could for the experiments - that's the highest my ESD tester can go. Of course that's not expected in real life, but to at least get some observations quickly with various parts. The point was to first see some light, then to figure out how to make it better, then figure out if it's practical for the application.

Ed

It's not necessary to detect light from a LED or neon lamp hit by a discharge - that's just another complication and efficiency loser. If you're in the realm of active circuits, the solution is trivial - you skip the light part (which was only appropriate for a passive system) and use electronic power gain to do the work. So now you have a battery to activate everything, and presuming the goal is still simply detecting the presence and polarity of the discharge, a simple transistor or other circuit driving LED indicators or such will suffice. The power gain can provide for boosting the indicator signal and easily stretching it in time.

Ed