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Re: Help with diagnosis of Tek 2465 Power Supply Problem
What page in service manual does in describe about doing this to test PSU. You can also test it in isolation by connecting one 2-ohm 25W to P232 and one 2-ohm 25W to J303 (+5VD) as described in the service manual. Running the PSU with the dummy load is a better idea especially if some voltages are overshooting.
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TDS540 Front Panel Schematic
Hi Guys,
I'm working on a restoration of a TDS540 with all the usual problems. It also has a not very clean square wave on the calibration signal, so have been looking at the front panel board to try and sort it. But, either I'm being a numpty and not looking at this right, or the board I have is a different version to what the schematics show, but I have not been able to find any other schematics. So can anyone with experience of the 540 help me out here? I've uploaded some photos to an album called TDS540 Front Panel (is that the right way to do this?). It shows the part of the schematic with the cal signal output coming from Q1, and a shot of the board (with the two screw heads) that is clearly quite different; the collector of Q8 is connected directly to the output. The other issue is that C12 (in the other shot) has no volts across it. So is it missing a supply rail, or is this just a signal cap? Without the correct schematic it is a little tricky to figure out. Thanks a lot, Ralph |
Re: Fault Finding with a Millivolt Meter
Back in the day (I haven't looked into this topic for about 4 decades), Princeton Applied Research made fairly decent lock-in amplifiers. They seem to be running about $300, or so on eBay.
If you don't need all the bells and whistles (and you understand the lock-in principle), you can whip one together for any given special purpose for under $15.00. I have done so many times. Stephen Menasian |
Re: Fault Finding with a Millivolt Meter
Moving slightly OT, I think Stanford Research are the Lock-In Amplifier
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people. (Among others) Talking $$$$ tho' Tim On Sat, 7 May 2022 at 03:22, Tom Lee <tomlee@...> wrote:
Re: Hacking a digital camera |
Re: Help with diagnosis of Tek 2465 Power Supply Problem
Hi Lyle,
My comments are below: On Fri, May 6, 2022 at 02:18 PM, <lylejlarson@...> wrote: Heres a summary of what Ive done:2465 schematic I found is missing proper measurement references, there is only one (REF) line. If you look at 2465B PSU schematic, which is almost identical, some voltages are measured wrt REF1 (inverter driver ground), and some measured wrt REF2 (U1030 ground). Voltages around Q1021 are measured wrt to REF2, makes more sense as U1030 supply is built on top of REF2. From your comments I assume you already know how to deal with measuring signals with floating high voltage reference points using an isolation transformer and safety precautions. ¡.Some possibilities: 1) There may not be enough load. Is fuse F1102 intact? From your comments about +10V I assume the PSU is connected to the rest of the scope. You can also test PSU in isolation by connecting one 2-ohm 25W to P232 and one 2-ohm 25W to J303 (+5VD) as described in the service manual. Others had the PSU running with only one 2-ohm 25W if you only have one such resistor. Running the PSU with the dummy load is better especially if some voltages are overshooting. 2) Another (unlikely) possibility is over voltage protection, U1030 pin 15 is kicking in. Pin 15 of U1030 wrt REF2 (ground of U1030) should be ~ 0.8V according to the schematic. If it gets close to 0V that says primary voltage of T1060 exceed the limit and error amp will turn off the switcher. If over voltage is the issue, and FB path is suspect, disconnecting the FB line should run the switcher at the lowest primary voltage. However, I don¡¯t think this fault puts the switcher in ticking mode so it is unlikely. 3) Over current, perhaps some caps or diodes in the rectifier section are bad. R1050 is the sense resistor. if Q1040 turns on, it turns off the supply to U1030. PSU is disabled until C1023 charges again and C1025 charges back to trip voltage of Q1021 network. Once Q1021 turns off, its emitter needs to charge back to ~ 20V or so before it turns on again because of the hysteresis through R1024. You can tell if overcurrent is the issue by measuring the voltage across C1023 and C1025 wrt REF2. If C1023 drops below ~ 7V at ticking rate while C1025 is still above ~13.2V then over current is triggered. You can also measure Vbe of Q1040 but it would be more difficult with all the switching waveform. Over current circuit is interesting, it depends on CR1040 to be a Ge diode so that Q1040 is off until ~ 0.3-0.4V is dropped across R1050. Mentioning it just in case it was replaced with a Si diode. Time constant of ticking with a short would be similar to what you are seeing. The FB line has a very suspect shape. Dropping , I'm going toDisconnecting FB runs the switcher at its lowest output voltage, if ticking is still going on without FB line FB signal is not the issue. Using a dummy load and testing PSU in isolation doesn¡¯t apply any FB signal and it is a good test too. check LINE UP, and FB, then PWR UPLine Up and Power Up just tell the scope power is good. I don¡¯t think an error in those lines could put PSU in tick mode. This could also be the reason for over current. If only one driver is on, current is applied to one side of the transformer only and primary would look like a DC load. Q1060 and Q1070 should alternate at every pulse from U1030. Or if there is no drive to Q1060 and Q1070 there won't be any pulses in T1050 to keep switcher going. Since you are measuring some voltage at the secondary one of the driver transistors should be passing current though. Ozan On Fri, May 6, 2022 at 02:18 PM, <lylejlarson@...> wrote: ...I can think of two possibilities (not to say these are the only two possibilities): 1) There may not be enough load. Is fuse F1102 intact? From your comments I assume the PSU is connected to the rest of the scope. You can also test it in isolation by connecting one 2-ohm 25W to P232 and one 2-ohm 25W to J303 (+5VD) as described in the service manual. Running the PSU with the dummy load is a better idea especially if some voltages are overshooting. 2) Another possibility is over voltage protection U1030 pin 15is kicking in. Pin 15 of U1030 should be ~ 0.8V according to the schematic. If it gets to close to 0V it will turn off the switcher. If over voltage is This could be related to FB signal, disconnecting the FB line should run the switcher at a lower primary voltage at T1060.
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Re: Fault Finding with a Millivolt Meter
Re: Hacking a digital camera
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Removing the IR filter won't make much of a difference. The objects have to be *very* hot in order to have any appreciable IR emission at wavelengths short enough for a silicon-based camera. With a bandgap of 1.2eV or so, you aren't going to see anything with greater than 1um wavelengths. Think of how hot something has to be to glow red, and back off a little. If you have parts that hot, you won't need a camera to tell you that! --Cheers Tom -- Prof. Thomas H. Lee Allen Ctr., Rm. 205 350 Jane Stanford Way Stanford University Stanford, CA 94305-4070 On 5/6/2022 18:13, James55 wrote:
Hi fellas, thanks for the input, it all helps. |
Re: Fault Finding with a Millivolt Meter
Interleaved:
On 5/6/2022 9:13 PM, James55 wrote: Hi fellas, thanks for the input, it all helps.Likely the best.? The 50% duty cycle is only for an HP current tracer, which detects fluxuating magnetic fields with a rather delicate and expensive hall effect sensor.? The idea is that with a shorted node to ground, the output that is trying to drive it puts a relatively large current pulse on the track.? With the sensor properly adjusted, you follow the tracks on the board and see which one has the greatest current.? Once you get to a pin (or a part) then you've found it.? High impedance inputs (functioning inputs) don't draw all that much current, so you're tracking the highest current on a track.? The 50% is arbitrary, and depending on whether or not you're trying to debug a signal line (let the system run as normal or in a loop) or a power line (inject a signal), the frequency will be significant.? A working 10 uf capacitor across a signal line would make a difference in bypassing the signal to ground (and thus reducing it).? If you don't have the probe, it's just a matter of academic interest. Most signal generators have a relatively low output impedance. Some (PG506) have a 50 ohm impedance, which turns out to be a 50 ohm series resistor, giving 1/2 the amplitude when terminated in a 50 ohm load (front panel gives sordid details).? If, for some unknown reason, the generator was made to drive only high impedance loads (not sure why one would do that), then the generator couldn't output enough power to wiggle a power rail enough. Again, only for use with a specific current sensor probe.? (rare, hard to find, and expensive).? More a matter of saying "if you have one, then you can try......".? I suppose that if you wanted to, you could probe the parts with a scope probe looking for the signal, but it wouldn't work all that well. DC tends to ignore capacitive reactance to ground (power line filter capacitors).? So the method was presented more of an "if you want to try this".? On a signal line, there are no bypass capacitors, and therefore, letting the existing drivers on that line is optimal. The answer to that is no, it won't.? Most cameras work on near infrared, which is likely the heat energy emitted by several thousands of degrees.? I have two sony cameras that can do that, and I've never seen anything remotely resembling a heat signature from them.? The IR given off by room temperature objects is far lower in frequency, less energetic, and below the threshold of most camera CCDs.? You need a special thermoelectric (or pyroelectric) sensor for that, IIRC, there's a certain amount of thermal inertia involved, which limits the response rate.? (I've seen 5-6 FPS, rather than 30+ on standard IR or visual sensors). Harvey
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Re: Fault Finding with a Millivolt Meter
Hi fellas, thanks for the input, it all helps.
@ Harvey; Nicely outlined. You've helped clarify a few things which weren't so clear. The feeding a 50% duty cycle signal shall have to wait. My intention right now is to nail the technique in finding shorts by analyzing the millivolts One more question, would be, "how might one find out if the tester has a high impedance?" There is no mention in the manual. @ Aldue; Yes, an infrared camera is definitely on the horizon, in fact, I do have one back in Europe. Has anyone ever tried hacking a 'normal' digital camera by removing the IR filter lens to see if the components glow when hot? That might be my best option here. @ Ed Breya; I'm currently in Rio, so obviously have access to lots of LIA's... What color were you thinking? No... apologies for being silly, but don't have access to a Lock-in Analyzer, tbh I have never heard of one. That said, I do appreciate the input and shall look further into them. My goal is ultimately to fault-find as quickly as possible, regardless of which technique or apparatus is used. I'm still a hobbyist so still accumulating tools and testers. The reason for asking about the millivolt method in particular was that following a prior thread, it became very clear that it was something quite basic which was missing from my repair 'armory'. Like Jim Ford however, I am intrigued as to recommended makes and models. Appreciations to you all. James |
Re: Help with diagnosis of Tek 2465 Power Supply Problem
On Tue, Apr 26, 2022 at 08:30 PM, Ozan wrote:
Thank you Ozan. Please excuse my delayed response. Your whole comment was tremendously helpful. For instance,I had confused T1020 and T1050 as a single transformer, partly because they are placed adjacently on the schematic. It looks to me T1020 is simply a common mode RF choke. C1025 initially charges from rectified line voltage through R1020. Once C1025Thank you for the helpful response. Much clearer now. Heres a summary of what Ive done: Using isolated PS503 and (2)PS501 Supplies I measured: Voltage across C1066: 0 Volts. Also, Voltage across C1025: 0 Volts. Voltage at Q1021-C: 1.5V Voltage at Q1021-E: Around 20V or more. Voltage at Q1021-B: 6.5V (!) Voltage at Q1022-C: 6.5V => No current thru R1023 Voltage at Q1022-E: ~6.0V. Voltage at Q1022-B: 6.5V Replaced Q1022. (With a 2n3704). U1030 starts (Pulsing) when the voltage across C1025 reaches about 24V. U1030 only turns pulses for 10mS or so, then stops for ~740mS, then comes on again for 1mS. Then on, then off ... Cycles like this as long as there is power. Connected to Line voltage. The ticking is back. With each tick, the 87V UNREG line spikes near 120 V, (but it varies considerably), 42V UNREG behaves similarly, but with ~1/2 the voltage. Blower motor turns about 1/2 rotation with each tick. C1066 mean DC voltage is only about 1.5V, but it charges rapidly when the pulses are present, almost reaching 12V. All of the supply outputs are all behaving similarly. Most exceed their listed voltage levels when U1030 stops pulsing. +10V Ref is slow to come up. The FB line has a very suspect shape. Dropping , I'm going to check LINE UP, and FB, then PWR UP Pulses seem clean at U1030.9, but weak and faulty (not clean pulse) throughout the "Inverter Drive" Section. Will post some waveform pics, when able. Thanks, Lyle |
Re: Proper Way to Pull Single-Ended Connectors?
I'd thought about shrink tubing as well but if I can get appropriate DuPont holders, I'll probably to that route. I'm pretty sure the wires are color-coded such that brown is pin one, red is pin two, etc., so at least I should be able to get them connected in the proper order. Unfortunately, this one (and I don't think many, if any, in this scope) are flat-cable. That would have been handy.
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Thanks, Barry - N4BUQ ----- Original Message -----
From: "Bruce Atwood" <CCDman1@...> I also had a blue one disintegrate to dust on my 7904. I put shrink tubing |
Re: Fault Finding with a Millivolt Meter
Ooh, shiny!? Lock-in Amplifier (never heard it called an Analyzer before) - now I want one!? Onto the wishlist it goes.? Any recommendations for make and/or model, Ed?? Or Steve H. or anybody?? TIA.? ? ? Jim FordSent from my T-Mobile 4G LTE Device
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-------- Original message --------From: "Ed Breya via groups.io" <edbreya@...> Date: 5/6/22 10:48 AM (GMT-08:00) To: [email protected] Subject: Re: [TekScopes] Fault Finding with a Millivolt Meter Do you have access to a lock-in analyzer (LIA)? If so, you can force some reference current, say at 10-100 Hz, and do voltage probing. The LIA's large dynamic range allows it to work with very small signals, and it's ability to distinguish phase lets you find real (resistive) shorts/overloads, while ignoring the capacitive loading of the filtering and bypass caps.Ed
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Re: Fault Finding with a Millivolt Meter
Do you have access to a lock-in analyzer (LIA)? If so, you can force some reference current, say at 10-100 Hz, and do voltage probing. The LIA's large dynamic range allows it to work with very small signals, and it's ability to distinguish phase lets you find real (resistive) shorts/overloads, while ignoring the capacitive loading of the filtering and bypass caps.
Ed |
Re: Proper Way to Pull Single-Ended Connectors?
Ignacio,
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Thanks for that tip. I have some of the four-pin type but will be getting some of the other pin-count versions. I didn't realize those would work. Thanks, Barry - N4BUQ ----- Original Message -----
From: "EB4APL" <eb4apl@...> Been there. You can replace the broken connectors with DuPont ones. They |
Re: Fault Finding with a Millivolt Meter
If you can borrow or afford one, a true infrared camera is way faster. IR
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imagers are much cheaper than they were two years ago. A camera that allows the user to set the range is best On Fri, May 6, 2022 at 11:52 AM Harvey White <madyn@...> wrote:
I'll see if I can summarize the concepts that I understand. |
Re: Fault Finding with a Millivolt Meter
I'll see if I can summarize the concepts that I understand.
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The basic concept is that you measure the voltage drop across each suspicious component and look for the lowest drop.? Another concept would be that the shorted part would be hotter than the rest, and would be detectable on a thermal camera. The caveat is that the power supply that is feeding the voltage to the board should be current limited to avoid burning out series filters, and actually blowing up the shorted part.? The supply should be voltage limited to the nominal supply voltage being simulated, and current limited (IMHO) to about 100 to 500 ma, depending on the original supply current.? Limiting the supply current also keeps from damaging traces on the board. The wiring on the board can be in two forms, one is a single supply rail with all parts hanging off it, another could be a divided set of feeds from some central point, or a combination of the two.? This depends on board geometry and trace routing, none of which will be indicated in the schematic. The concept of coloring in the parts on a copy of the board is simply to show you which ones to check and which to ignore.? You might consider putting all the capacitors in one color, and all the chips in another. Considering the straight line model, think of a long extension cord with lamps plugged in every few feet.? Since at a low voltage, the parts are not likely to draw much current, from the end of the string to the short, most voltages will be the same. At the short itself, you'll get the same voltage as down the string.? At the next part in the string, the part sees across it the shorted part /with the added resistance of the traces to that part, both ground and supply/.? This means that the voltage across a part upstream of the shorted part should be higher.? That voltage ought to increase up to the point where the supply is connected. Since these resistances are quite small, the use of a millivolt meter is important, and with a high input impedance.? That high input impedance minimizes the effect of a slightly inconsistent connection. It is also important to measure the voltage drop across the part itself, not with reference to a ground.? Since you don't know where the ground goes, you don't know how much a ground trace, ground flood, or ground plane contributes.? Best to measure across the part itself. In the case of a split supply, one branch should show the fault (assuming there's a single fault). There are other techniques.? The heating test requires more current and a thermal camera. Another technique would be to feed the power supply with a 50% (or so) duty cycle square wave voltage limited to the supply rail voltage and current limited to about 50 ma. or so.? HP made a non-contact current probe that was designed to find a shorted node to ground.? It could be used to trace the supply track from the main input supply terminal to the shorted part.? I think I've tried that and it works within limits (pulses will be shorted out by the capacitors, but by how much?).? That current probe is rather rare and expensive, which makes the millivolt meter technique the best one. Harvey On 5/6/2022 7:15 AM, James55 wrote:
Hi all, |
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