Lars Ahlstr?m
Yeah, I understand. Its just to accept.
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But the whole brain of mine want to give the result [ sqrt(-1) = -1 ] !!! =) If I draw a carthesian coordinate system and pinpoint X=1 and Y=1 I get a square of the sides = 1. The square is 1. meter, mm, inch, foot or whatever And if I pinpoint X= -1 and Y= -1 I get a square with the sides -1, and the area is then -1. foot, inch, yard or whatever. The root of that square is -1 !!! The root of -9 is -3 !!! (I think¡;) That¡¯s why I cant accept it, I guess. I also see cube root of -1 = -1, no problem! ;) But Im just a fool¡ /Lars -----Ursprungligt meddelande----- Fr?n: TekScopes@... [mailto:TekScopes@...] F?r arthurok Skickat: den 30 december 2006 23:57 Till: tekscopes@...; Kuba Ober ?mne: Re: SV: [TekScopes] Invitation for another exchange of questionably useful information. its a shared "delusion" ----- Original Message -----
From: Kuba Ober To: tekscopes@yahoogrou <mailto:tekscopes%40yahoogroups.com> ps.com Sent: Saturday, December 30, 2006 12:02 PM Subject: Re: SV: [TekScopes] Invitation for another exchange of questionably useful information. On Friday 29 December 2006 05:38, you wrote: That post reminds me of my own high school drama: The j-omega method.brains lack of fantasy) of the ¡°root of minus one¡±.Well, it's an abstract concept, I guess it's better treated like one. Your only "idea" should be of the properties of this number, and some applications that suit your interests. I don't think I have any other "ideas" here. You can go pretty far by just knowing that the number has "otherwise" normal properties, i.e. you treat it like any other number that only doesn't "mix" (in addition) with real numbers. And when you square it, it goes away. I did my grad level vibrations course without using any other "higher" properties (whatever those might be) of sqrt(-1). I guess it shows what a powerful concept it is: only minimal properties are necessary to extract a lot of mathematical expression power. Cheers, Kuba [Non-text portions of this message have been removed] [Non-text portions of this message have been removed] |