On Thu, Mar 18, 2021 at 04:39 PM, Albert Otten wrote:
In this case, the loaded output is not (50/650)*120 V. The fast rise holds for
the edge from negative to GND where the output tubes are cut-off. Only then
the output impedance is 600R. The amplitude is determined by the current that
the tubes can deliver. About 0.24 A. Gives 12 V in 50R.
Thanks for that further explanation, Albert. The 240mA max is written on the front plate, with the 120V max.
Raymond
Raymond Domp Frank