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The Tayloe detector wants two LO signals that are in quadrature (phase shifted 90 degrees) to one another. ONE way to get this phase shift is to have a signal at 4X what you want to receive, and then to count it down. That's what's done in the original design.

What Hans has done is to program the 3532 (using his bag of tricks!) to directly generate two LO signals directly that are shifted 90 degrees relative to one another. So no divide by 4 is required!

Short story: He used different way of generating the quadrature LO, but the detector works the same way as described in the papers you're reading.

73, Paul -- AI7JR

Hello,

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After assembling the RX module it has been working great, and i'm really happy with the performance aswell, a wire in my basement was able to pickup FT8 across the sea!

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Anyway, I'm confused as to how it even works, as the manual says this: "The two outputs of this circuit (at pin 6 and pin 9) have the same frequency as the receive frequency (1/4 the LO frequency), but are offset from each other by a 90-degree phase difference", I know it is how the chip is setup, to make the frequency 1/4th of the LO, but why? Every paper I have read about the tayloe detector mentions that the MUX (FST3532 in this case) requires a 4xLO in to see a quarter cycle of the input at each output. It's on the first page of the tayloe mixer PDF. Is there something I missed, or am I interpreting the schematic wrong? Because how I am looking at it now makes me believe the receiver should actually be receiving 1/4th freq of the already 1/4th cut 4x LO.

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Anything will help, thank you very much.

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Paul -- AI7JR