Hello,
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After assembling the RX module it has been working great, and i'm really happy with the performance aswell, a wire in my basement was able to pickup FT8 across the sea!
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Anyway, I'm confused as to how it even works, as the manual says this: "The two outputs of this circuit (at pin 6 and pin 9) have the same frequency as the receive frequency (1/4 the LO frequency), but are offset from each other by a 90-degree phase difference", I know it is how the chip is setup, to make the frequency 1/4th of the LO, but why? Every paper I have read about the tayloe detector mentions that the MUX (FST3532 in this case) requires a 4xLO in to see a quarter cycle of the input at each output. It's on the first page of the tayloe mixer PDF. Is there something I missed, or am I interpreting the schematic wrong? Because how I am looking at it now makes me believe the receiver should actually be receiving 1/4th freq of the already 1/4th cut 4x LO.
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Anything will help, thank you very much.
@sqk