Add to that -- termination at the operating impedance level will mean (if it's 50 ohm out) a 50 ohm resistor across the driven and return lines of each output, which naturally shunts all output to ground. If you just need to pull the unused outputs down, a 1K resistor is what's usually specified by the? manufacturer, but you should check the datasheet first. I certainly would NOT just tie an output to ground, because that gives a zero-ohm, extremely low impedance path for any stray energy to get out.? Kinda like (from my previous "water" analogy) punching a hole in the side if the toilet tank because the flapper valve is leaking. There's a good possibility that SiLabs may have missed it on this one, since we do things that they may not do.? So opening a dialog with their tech support may be a useful idea.? And as it happens, they're in the same town I am, and I'm a tech writer in need of a job right now ... maybe I should ping them too. I'd like to thank all who've shown interest in this topic. 73 Jim N6OTQ On Fri, Jan 18, 2019 at 10:37 AM Jerry Gaffke via Groups.Io <jgaffke=[email protected]> wrote: Programming the chip to drive an unused output low, and then externally shorting that pin to ground, |