OK, really quick...
Your math is correct.
+37dBm - 40dB= -3dBm
To get to -25dBm --> you need +37 dBm - 62dB = -25 dBm
73,?
Geoff --> AB6BT
On 1/23/2025 1:03 PM, Joe Tomasone
wrote:
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This all makes sense.? ?So what I do not understand
is how with a 5w transmitter - which (if my math is right) is
37dbm, a 40db attenuator gets you to the minimum -25dbm safety
threshold for the Ultra.? It would seem to me that it is -10dbm
and therefore (risking) causing damage, no?
Joe
OK, I'll try:
Your confusion may come from not
understanding the dB and logarithms related to actual
power.
1)? The advantage in
reasoning/thinking in dB space is that the dB, like
logarithms, add and subtract directly.?
2)? So converting to dB in power,
usually dBm (dBmilliwatts or 1E-3 watts), allows one to
directly deal with powers in adding and subtracting
attenuation directly.?
3)? Also realize that every 10
dB, be it power or attenuation, is a power of 10 greater
or lesser.? So if you start with 1-watt and insert a 10 dB
attenuator, you end up with 100 mW.? If you start out with
10-watts and insert a 20 dB attenuator, you end up with
100 milliwatts.? Remember this as it makes things easier
without converting to dBm or dBw (dBwatts).
4)? How to convert from RF power
to dBm, again, remember dBm is in dBmilliwatts or 1E-3
watts which is 0.001 watts.
5)? Convert power to dBW: ? dBW =
10 x log10 [power in watts].? That "10" after the log
indicated log[base 10].? The Brits. use the Neper which is
log[base e], the "natural logarithm".We're concerned only
with log[base 10]. ?
Example:?? Assume you have
10-watts.? So:? dBW = 10 x log [10-watts] = 10 x [1] = +10
dBW
6)? Since we now know dBm is
0.001-watts or 30 dB BELOW 1-watt, we must add that 30 dB
to our +10 dBW to express the power in dBm (remember,
there are "more" dBm's in a watt than a single watt or
dBw).? So, our 10 dBW beomces +40 dBm.?
Now you can add and/or subtract
directly the value of any attenuator you install to get
power in dBm.??
Dave - W?LEV? ? ? ?
I've been reading the responses to my own
thread on here and watching several YouTube videos and
still feel like I do not have a good handle on the
attenuation required.??
In the videos, I have seen multiple hams use a 40db
10w attenuator with no internal attenuation to test?a
5w HT with apparently no ill effects.? ?I've also seen
some use more attenuation for lower power outputs.?
?To my understanding from reading what has been
written here and these videos:
1. I would need around 60-80db of attenuation to
safely input a 1w signal into the Ultra.?
2. I should not use the internal attenuator - or,
alternatively, I should.?
3. I should use a variable attenuator in
conjunction with the 40db attenuator, or I should just
use 2 40db attenuators, or I should use the 40db
attenuator plus the internal on "auto".?
4. I should use a CleanRF.com RF-S2K & dummy
load with a 40W attenuator or by itself (but the
CleanRF is only specced?for 3-30Mhz, so I don't
understand how it would work anyway...)
I could really use some authoritative answers on how
to safely test VHF/UHF/HF rigs without letting the
smoke out of the Ultra.? ?I have the 40db attenuator
(10w, covers the spectrum) already. I'm not sure what
else I need to obtain.
Thanks,?
Joe AB2M
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