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I also just received notice from USPS that the S-A-A 2 is in transit. With any luck I should receive it within a few days. I placed my order on the 8th of March, so given the current state of affairs

On Wed, Mar 25, 2020 at 02:22 PM, Rune Broberg wrote: Hi all, An S-A-A 2 device is on its way to me, and I will update nanovna-saver as soon as possible when I get it. I am sorry for having taken so

The Smith chart assumes that the impedances have been "normalized". Just divide by 50 to get one in the center Bob [email protected]> wrote:

Thanks for the reference. Not bad first response, appreciate that very much. Cannot say much about the rest of them. In future I will limit my posts to "how much is 1 and 1 " , asking to avoid sermons

Hi all, An S-A-A 2 device is on its way to me, and I will update nanovna-saver as soon as possible when I get it. I am sorry for having taken so long to get a new version up, but real life has

Thank you for the suggestion, from which I see now that I have to correct what I wrote, as follows : for the newcomer, the whole Great Idea of that very difficult to learn Smith Chart is just of

I believe that the scale in question is linear... but it's measuring the "reflection coefficient", not "impedance". It has a value of -1 at the "zero ohms, short circuit" end, a value of 0 in the

On Wed, Mar 25, 2020 at 12:21 PM, Holger Müller wrote: Subject has arrived to me today. Hope I find some time to check and test it with NanoVNA-Saver soon.

Like a slide rule. Accurate enough to get useful results and visualize what's happening in a system. You can be much more accurate by using SimSmith. -- Art Greenberg WA2LLN art@...

Hi, $Subject has arrived to me today. Hope I find some time to check and test it with NanoVNA-Saver soon. ciao Holger (DG5DBH)

Smith Chart : In this computer era, this extremely high-effort demanding, highly-inaccurate, old-time graphics tool became completely obsolete, because it is a totally useless one in every other

Because I dropped a zero. :-) For example, the point 1.2 + j.7 is really 60 + j35 in a 50 Ohm system.

Why isn't the example = 60 + j35 ??? <snip>

The Smith Chart coordinates are normalized to the impedance of whatever system you are using. This is usually 50 Ohms so the 1.0 in the center of the chart is 50 Ohms resistance, 0 Ohms reactance. You

If you're interested in modifying/hacking/playing with several of the NanoVNA apps written in Python, there is an open-source area on Github with a complete intro on the subject:

There is no scale as such. The mathematics provides the translation from the rectangular Z coordinate system to polar and the result of that math transformation yields the curves your are referencing.

Yes but the gentleman wants to know about the scaling of those curves which are defined by the uniquely derived? equations as shown in the URL I posted. Gedas, W8BYA EN70 Gallery at http://w8bya.com

Actually, the Smith chart is "normalized" to whatever the impedance that you are working with, usually 50 but could be 75 or 450 if open wire feed line.The operation to compute is as John described,

Hi, The scale is neither linear nor logarithmic, and I’m not sure what it is. Luckily it does not matter if you just want to use the smith chart. Generally for radio work the centre is defined as 50

Not a math wiz here but one of the best ways I learned about the chart back in college was to see the mathematical calculations (and thus derivations) for the actual circles. The smith chart has