Why isn't the example = 60 + j35 ???
Because I dropped a zero. :-)
For example, the point 1.2 + j.7 is really 60 + j35 in a 50 Ohm system.
On Wed, Mar 25, 2020 at 1:54 PM lgo51 <larryo@...> wrote:
Why isn't the example = 60 + j35 ???
At 11:24 AM 3/25/2020, Carey Fisher wrote:
The Smith Chart coordinates are normalized to the impedance of whatever
system you are using. This is usually 50 Ohms so the 1.0 in the center of
the chart is 50 Ohms resistance, 0 Ohms reactance.
You can take any point on the Smith chart and convert to actual Ohms by
multiplying by the impedance of the system (usually the main transmission
line) you are making measurements in.
For example, the point 1.2 + j.7 is really 6 + j35 in a 50 Ohm system.
The reason for this is that you might be using different impedance
transmission lines in a design and this makes it easy to move between
different impedances.
BTW, there are Smith Charts available with 50 Ohm markings.
<snip>
--
Carey Fisher
careyfisher@...
