The problem with that, of course, from a basic error analysis perspective,
is that any other values used in any equation using a value of Z? with 12
(or 14) significant figures will probably have many less than 12 (or 14)
significant figures and will dictate that the result of the calculation is
only valid with the number of significant figures of the number in the
equation with the lowest number of significant figures. This is basic
proper error propation practice.
A trivial example:
In the expression
n = Z?/2.0 = 188.365156706,
where Z? is written as 376.730313412,
Strictly speaking, the "6.730313412" part of
376.730313412 is meaningless, since the value of the numerator only has two
significant figures. But we would allow 377/2, giving 188 (or 188.5, where
the general practice of allowing one extra significant figure in the result
is used).
(Lol. I'm not sure if I expressed that as concisely or correctly as
possible).
DaveD
KC0WJN
On Sun, Jan 26, 2025 at 12:15 ww6x via groups.io <ww6x@...>
wrote:
The impedance of free space is Z? = 376.730313412(59) ¦¸. I, for one, will
not stand for any measurement with less accuracy.
--
ww6x
On Sun, Jan 26, 2025, at 9:00 AM, Jerry Stuckle wrote:
It is close enough for YOU. It is NOT close enough for everyone.
