--- On Monday, March 7, 2022, 12:31:57 PM EST, Antonio (EA7HJ) via groups.io <ea7hj@...> wrote:
I have always used the Smith's Chart with the standardized values
of the R¦¸ +/- jXXX impedance. In the NanoVNA H4 the measurement
makes it as R¦¸ + XnH or R¦¸ - XpF. My question is how I can convert
the inductive/capacitive reactance of the impedance of NanoVNA to
the "j" value standardized in the Smith Chart.
For an inductor, Xl = j * omega * L
For a capacitor, Xc = 1 / (j * omega * C)
omega = 2 * pi * freq
j = sqrt(-1)
73,
Ken N8KH
