Minor correction to my last post:
< 1.5 volts into 50+50=100 ohms, so 1.5/100 = 0.015 ma.
1.5 volts into 50+50=100 ohms, so 1.5/100 = 15 ma.
Jerry, KE7ER
On Sat, Aug 22, 2020 at 08:55 PM, Jerry Gaffke wrote:
Assuming it has a voltage source of 3.0v pk-pk and that we put a 50 ohm
capacitively coupled
load on the output pin, it's effectively driving 1.5 volts into 50+50=100
ohms, so 1.5/100 = 0.015 ma.
