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Hi Jeremy,

The entire thing is integers until the makestring.

I compiled and ran it before taking another guess in public ... ?

On Jan 3, 2019 1:46 PM, "Jeremy Weatherford jweather@... [Crestron]" <Crestron@...> wrote:

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You're mixing levels... hex escapes like \xFF are interpreted by the compiler.? You're sending literal strings with 4 characters per byte: backslash, x, high nibble, low nibble.? Should be:

makestring(Output$,”ABC\x00\x00\x%c%c%c%c\r",byte4, byte3, byte2, byte1);

%c prints a single byte (or Character) with the specified value.? It is the dynamic equivalent to using the static \x00 escape.

On Thu, Jan 3, 2019 at 2:51 PM Kol Johnson kol.mstc@... [Crestron] <Crestron@...> wrote:

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I had to try it to find out . . . Too easy.? Of course it didn’t work . . .

Since you have converted the input to a long_integer, you already have the 4 bytes. ??

long_integer ? li_number;

integer ? byte1, byte2, byte3, byte4; ? ??

??

? ? byte1 = li_number & 255; ?// extract the lowest byte

? ? byte2 = (li_number}}8) & 255; //shift the number to the right by 8 bits (1 byte) and extract the next lowest byte

? ? byte3 = (li_number}}16) & 255; //etc.

? ? byte4 = (li_number}}24) & 255; //etc.

??

? ? makestring(Output$,”ABC\\x00\\x00\\x%02X\\x%02X\\x%02X\\x%02X\r",byte4, byte3, byte2, byte1);

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