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Boonton Q Meter Thermocouple & Precision Resistor
The question was asked previously why the thermcouple heads you can see the char marks on the Bakelite terminal board of an exemplar |
On Sun, Aug 14, 2022 at 08:31 AM, Chuck Moore wrote:
<snip> That's Brooke Clarke, who is a member of this list. <snip>
Ah, so the sense wire gets very hot. I assume that means ambient temperature changes are no so significant, as it's so far above ambient. I thought I read in the 260-A manual that the RF signal generator only run at 50% of the power that could destroy the thermocouple, implying this would not happen like it did in the 160-A But maybe I got that wrong. Em, I like to design things with a bit more to spare than that! Thank you. Your comments certainly help understand why the things burn out so easily. How does one know if the thermocouple assembly is faulty? I ask this from the view of a person that has bought a supposedly working 160-A from eBay from a seller with a rather poor feedback. The attraction to the auction was the unit appears in good physical shape and that the shipping charges were less than $30 from the USA to the UK. I don't yet have the meter, but would like to know how to run some checks when it arrives. I do have a couple of Boonton Q standard inductors. One covers 50 kHz to 150 kHz and the other 150 kHz to 450 kHz. Dave |
开云体育With all the talk of ‘Q’ meters and CMM’s, those interested might like to take a look here… ? ? John’s excellent pages give some incite into the quality of the UK made products of the time… ? Regards Nigel Adams – Marconi Instruments Heritage Collection. ? From: [email protected] <[email protected]> On Behalf Of Dr. David Kirkby, Kirkby Microwave Ltd
Sent: 15 August 2022 10:09 To: [email protected] Subject: Re: [Test Equipment Design & Construction] Boonton Q Meter Thermocouple & Precision Resistor ? On Sun, Aug 14, 2022 at 08:31 AM, Chuck Moore wrote:
<snip>
That's Brooke Clarke, who is a member of this list.
Em, I like to design things with a bit more to spare than that!
Thank you. Your comments certainly help understand why the things burn out so easily. |
Dave |
Labguy
开云体育I just had a look at Boonton Radio Corp “The Notebook” Notes 1 to 10. There are many excellent articles on Q-meters, including how to replace the thermocouple in the 260A. ? They can be downloaded from: ? https://www.rsp-italy.it/Electronics/Magazines/index.htm ? Cheers, George VK2KGG ? ? From: [email protected] [mailto:[email protected]] On Behalf Of nigel adams via groups.io
Sent: Monday, 15 August 2022 8:58 PM To: [email protected] Subject: Re: [Test Equipment Design & Construction] Boonton Q Meter Thermocouple & Precision Resistor ? With all the talk of ‘Q’ meters and CMM’s, those interested might like to take a look here… ? ? John’s excellent pages give some incite into the quality of the UK made products of the time… ? Regards Nigel Adams – Marconi Instruments Heritage Collection. ? From: [email protected] <[email protected]> On Behalf Of Dr. David Kirkby, Kirkby Microwave Ltd ? On Sun, Aug 14, 2022 at 08:31 AM, Chuck Moore wrote:
<snip>
That's Brooke Clarke, who is a member of this list.
Em, I like to design things with a bit more to spare than that!
Thank you. Your comments certainly help understand why the things burn out so easily. |
开云体育All of the Boonton notebooks are st the Hewlett Packard archive I don't know how to copy the url on my cell phone but Google found it.? -------- Original message -------- From: "Chuck Moore via groups.io" <wd4hxg@...> Date: 8/15/22 5:03 PM (GMT-08:00) Subject: Re: [Test Equipment Design & Construction] Boonton Q Meter Thermocouple & Precision Resistor https://www.rsp-italy.it/Electronics/Magazines/index.htmThank you George. Finding all of Boonton's notes in one spot is a real gem. Regards Chuck WD4HXG |
In the model 260, the oscillator supplies 1 amp of RF current to produce 20 mV across the 20 milliOhm LC series resistor. This would be 20 milliWatts across the resistor, but 200-300 milliWatts in the thermocouple if it is 0.2-0.3 Ohms.
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I determined the 1 Amp current from the calibration procedure where 4 Volts applied to the voltmeter section equals a Q of 200. Q = Vout / V in, thus Vin = 0.02V. The model 160 has the same 4V = Q of 200, but a 40 milliOhm resistance so current is only 1/2A. The 160 thermocouple then MIGHT be less fragile than the 260. John On 8/15/2022 6:33 AM, Chuck Moore via groups.io wrote:
Dave |