I may be premature in answering this question because it may have already been answered.
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The output impedance of an emitter follower is the source impedance driving the base divided by the current gain of the transistor plus one.? This value is in parallel with any resistors that may be connected to the emitter either DC or AC coupled.? So it goes back to the impedance of the generator that is connected to J6.? Then the output impedance is multiplied by the turns ratio squared of the transformer.?
I'm not sure I agree, the schematic I posted shows a 75¦¸ resistor across the transformer as Zo. And I'm waiting for an analysis of the impedance converter amp to see if we can find it's output impedance. I'm speculating that it is low, but the 220¦¸ resistor has me questioning. ????????????????????? Mikek
