I believe that the 1854-0332 is a 2N3866A; your 2N5109 should indeed
be a very reasonable choice here.
That still leaves us with an order of magnitude discrepancy in
output resistance.
By any chance, are you powering your breadboard circuit off of a
positive supply? If so, did you reverse the polarity of the output
cap?
And is your circuit soldered together, or are you using a solderless
breadboard?
--Tom
--
Prof. Thomas H. Lee
Allen Ctr., Rm. 205
350 Jane Stanford Way
Stanford University
Stanford, CA 94305-4070
On 9/16/2022 22:44, Steve Ratzlaff
wrote:
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Q1 (input) is HP 1854-0091--no "2Nxxxx" equivalent transistor
listed in HP equivalent list. Q2 (output) is HP 1854-0332, again
no equivalent transistor listed. Both are TO-5/TO-39 case. I
think a 2N5109 is a reasonable choice for trying the circuit in
the breadboard.
Steve
On 9/16/2022 10:18 PM, Tom Lee wrote:
Thanks for checking that, Steve.? Unless the 2N5109 has a
surprisingly high parasitic emitter resistance, there's still
about a 10x gap to be closed.
--Tom
--
Prof. Thomas H. Lee
Allen Ctr., Rm. 205
350 Jane Stanford Way
Stanford University
Stanford, CA 94305-4070
On 9/16/2022 22:14, Steve Ratzlaff
wrote:
And the output capacitor I used was 100 uF/25 volts, with
measured 100 kHz ESR of 0.26 ohms.
Steve
On 9/16/2022 10:00 PM, Steve
Ratzlaff via groups.io wrote:
As noted, first test was at -40 dBm. I raised the level
just now to max, -17 dBm--very little change from
before--the output impedance decreased about 0.03 ohms for
each frequency.
Steve
On 9/16/2022 8:55 PM, Tom Lee
wrote:
Those numbers have a believable trend, but the magnitudes
seem too high. I don't know what the parasitic emitter
resistance is of a 2N5109, but I would be surprised if it
were bigger than an ohm. The output capacitor's ESR adds
to that, of course, but a good cap shouldn't have several
ohms of ESR. So, if you include realistic parasitics, the
output resistance should be an ohm or less. The milliohms
number I gave earlier is the ideal value you would get in
the limit of no parasitics.
How large an excitation are you using to probe the output
Z?
Tom
--
Prof. Thomas H. Lee
Allen Ctr., Rm. 205
350 Jane Stanford Way
Stanford University
Stanford, CA 94305-4070
On 9/16/2022 19:48, Steve
Ratzlaff wrote:
I breadboarded the circuit just now using 2N5109's
and swept the output Z with the DG8SAQ VNWA, 10 kHz-30
MHz. The circuit draws 117 mA; the output transistor
draws 84 mA. The output impedance is mostly flat,
gradually rising after about 10 MHz.
50 kHz 4.23 ohms
1 MHz 4.42 ohms
10 MHz 5.27 ohms
20 MHz 6.80 ohms
30 MHz 8.77 ohms
Steve AA7U
On 9/16/2022 5:44 PM, Mikek
wrote:
Someone sent me a private messaged and corrected me on
the output impedance of the 50 to 1 transformer,
it is 0.001¦¸ or 1 milli¦¸. So, impedance ratio of 2500
x -.001 = 2.5¦¸ primary impedance. I'm not sure I know
how to figure the output impedance of the
power amp in the HP4342A, I would have thought 220¦¸.
I'm posting the schematic of the impedance converter
the drives the injection transformer primary and
asking,
What is the output impedance of the impedance
converter?
????????????????? Thanks, Mikek