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Re: Making a Q-meter /


 

On Thu, 4 Aug 2022 at 14:00, Navmar <navmar@...> wrote:
You raise the issue here of how to generate a signal with very low source resistance.
How about this idea.
Consider a signal source feeding a resistive divider consisting of Rs (source) and Rl (load).? This gives the relationship? Rs/Rl = Vs/Vl-1. So Rs approaches 0 as Vs and Vl become equal.
If you introduce an ALC control loop that monitors Vl and attempts to make Vs and Vl equal then the effective Rs becomes small.

A worthy idea or not ?

I played with this a bit recently and could quite easily get Rs down to one ohm at 50MHz.? Its part of an idea to modernize the old Boonton 250 RX meter.?

Bill


Could you please sketch it out, as I am not following it.

Dave

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