On Fri, Aug 19, 2022 at 04:19 AM, Mikek wrote:
Following the 2 pF cap C3 is a 56 pF feedthru cap, C4, to ground, so the capacitive divider is 2 pF/(56 pF + Q1 input C + C1.3 pF, in series with 2.87K).
I'm not getting it, maybe math failure (on my part). I calculated at 1MHz. Reactance of 56pf = 2,844¦¸, 1.3pf = 122,489¦¸, (FET guess) 5.2pf = 30,622 and the R = 2870¦¸.
?Total = 158,825 / 2pf reactance of 79,618 = 0.5¦¸.? That does not seem right!
Any ideas?
Just noticed a small error, 1.3pf reactance and 2,870¦¸ do not add directly, I'll ignore it as it's small.
???????????????????????????????????????????????????????????? Thanks, Mikek
