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QMX suffers zero negative impact from deleting L401 (with measurements)
In previous episodes of this saga - The frontend is complaining quite visibly! Now let's tune the NanoVNA to 1700 khz, the highest frequency in the AM radio band: |
Hi Stephan, as Gunnar begins to suggest - the QSD will respond far more strongly to frequencies at one third of the LO injection frequency than those at one half.? So tuning your NanoVNA around 1.1667 might well produce a significant audio tone (but depending, as you say, on the attenuation afforded by antenna and tuner), as might the fifth undertone around 700KHz.
As for series inductors -? of course in isolation they don't result in low frequency roll-off but in series (or, for that matter, in parallel) with a capacitance they can usefully emphasise a wanted frequency vs unwanted lower frequency (as well as higher). 73 Rod G0VKX one time G8FJN (but sadly the authorities no longer allow me to hold both callsigns) |
Hi Bojan, Thanks for the screen shot example of how elsie works. I might have to see if I can get it to work on Wine emulator. One thing to keep in mind is that, because of the stray shunt capacitors at both sides of the inductor, the insertion loss of the BPF will be greater than predicted by your simulation. Also, for the same reason, the rolloff on the higher frequency side of the center freq will be steeper. That is both in simulation and in real life measurements. |
Can you please point me to how to modify the QMX to omit L401?The naive method I used was to short all of the pads that make up L401's footprint. The easier way that I realized later was to simply short pins 7 and 9 of IC402. BTW a clean square wave has only odd overtones, so the fist overtone for 1700 kHz would be 5100 kHzOh, of course, how silly of me. Bojan Naglic: I agree that you gain nothing at lower frequencies but you loose about 13 dB at the frequency you want.I'm not sure what this graph is trying to show? Rod Smith: So tuning your NanoVNA around 1.1667 might well produce a significant audio tone (but depending, as you say, on the attenuation afforded by antenna and tuner), as might the fifth undertone around 700KHzWell, yes, but this would be because the actual signal entering the radio actually contains that harmonic. Even a sharp bandpass or high pass filter that perfectly isolated the band of interest wouldn't filter this out, because it's a signal, not an artifact. A real AM radio station would not be allowed to generate harmonics so strong that they interfere with the amateur radio band, so if we're interested in the effects of nearby AM radio stations we're really only interested in the consequence of a strong signal at the station's fundamental frequency. I'm interested in seeing if there is a realistic scenario where an out-of-band signal generates an artifact in the band of interest, either in the form of a spurious signal or increased noise floor. The primary goal of my experiment was to see if even a very strong signal in the AM radio band, stronger than anyone could realistically ever expect to see hitting the front end of their radio, resulted in any ill effects. I'm fairly satisfied that between the high pass characteristic of C401/402/404, and the selectivity of the tayloe detector, that L401 and the construction challenges it presents is unnecessary for good performance. I welcome anyone to provide evidence to the contrary. |
KE0WVA,
Your doing a work around for a winding error. Your claims for BCI are not even close to my environment. I have many stations that are part of the eastern MA broadcast nexus most less than 7miles from my home and a few closer (AM broadcast) , so band pass and high pass is required here. In some cases weak designs (hobby and commercial) need a high pass filter to function well. Add to that more than a dozen hams on HF within 3 miles, some using 160 and even 630M. The series inductor is a low pass structure.? However the resonating capacitor in series creates a high pass node.? That they are resonant hopefully mid band is critical.? Winding L401 wrong is an error and should be fixed.? That you are not close enough to broadcast stations to not have issues is just good fortune. Study the circuit and do the sheet of paper analysis by eliminating the CMOS switch (IC402) and simplify it to L401 and C401/2/4 in series. For those that want to delete L401 a jumper from IC402 pin 7 to Ic402 pin9 eliminates L401 (shorts it out).? ? FYI IC402 is a dual 4 position switch so its easy to? see it how it all lays out. FYI: if it was really not needed Hans you have left it out and its a safe bet it was tested both ways.?? --- Allison ------------------ Post online only,? direct email will go to a bit bucket. |
I thought the third harmonic issue with Tayloe detectors was their susceptibility to detect signals at the odd harmonics of the VFO, so if tuned at 7mhz, signals at 21mhz would only be about 9db down ie the susceptibility to detect harmonics of the VFO frequency is not at one third of the VFO frequency.? A LPF is needed to knock down any signals at the harmonics and we already have that for the TX side.
The BPF tracking provided by the QSD provides attenuation of 35db only 20khz either side of the VFO frequency in the QCX (per QCX manual) who knows how far down it is several MHz down (when consider 80m VFO that might be impacted by MW frequencies). Great to see some testing and measuring being done on this issue of what impact the front end BPF circuit really has. 73 Simon VK3ELH |
Hi all I don't recommend deleting L401 which will have a performance impact - how much, depends on the circumstances. As previously discussed I don't believe the strong IP3 performance of the QSD eliminates any need for filtering. The often quoted narrow filter implemented by the QSD doesn't help protect the CMOS MUX switches against large signals, in my opinion. The sum total of everything hitting your front end can add up. I didn't like it when the uSDX evolved out of QCX with no BPF either... For the same reason. Just my opinion... 73 Hans G0UPL On Wed, Oct 18, 2023, 3:05 AM Kelly Jack <kellyjack1968@...> wrote: I thought the third harmonic issue with Tayloe detectors was their susceptibility to detect signals at the odd harmonics of the VFO, so if tuned at 7mhz, signals at 21mhz would only be about 9db down ie the susceptibility to detect harmonics of the VFO frequency is not at one third of the VFO frequency.? A LPF is needed to knock down any signals at the harmonics and we already have that for the TX side. |
Hi,
I agree totally that the BPF is needed here. Even more selective if there would be room for it. Strong signal will be demodulated at the first non-linear element in the receiver front-end, the mux in this case. And you can not get rid of it after that. I am sure many have experienced that during some latest contests. (CW, RTTY, ...) " Bojan Naglic: I agree that you gain nothing at lower frequencies but you loose about 13 dB at the frequency you want.I'm not sure what this graph is trying to show? " With my ad-hoc Elsie simulation I wanted to show that avoiding the L401 from the serial resonance circuit and leaving the C in lowers the sensitivity of receiver at wanted frequency! The first diagram shows the path with only remaining C and the second one with LC serial circuit as in QMX (here just as an example for the 9 MHz).? -- 73 Bojan S53DZ |
I totally agree with Hans here on the L401. Deleting the band pass filter in QMX would, IMO, ?probably turn it into a uSDX! With all the respect to their unique design disclosing the Atmega processor's capabilities with the right software, the uSDX ?family ( in its ?multitude of incarnations, including the (tr)u)SDX) has one huge flaw- a horrible front-end due to lack of BPF. I've compared once, the behaviour of my truSDX vs my 20m QCX ?in front of the strong signals, and the results were devastating for the uSDX. And the performance improved a lot when I hooked the uSDX to my EFHW antenna with tuned (resonant) matching unit, which was acting also, in this case, as an external BPF. So, I would grant the deleting of L401 in QMX ?"The Worst Mod of the Year" award! :) 73! Linas LY2H
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All, Let's not politicize an engineering decision. It's free to keep L401 or delete it in your own QMX build for self-satisfaction, but I feel that this thread has become campaigns trying to persuade others that their idea is right. L401 is just an engineering decision point. I have a position on that (previously expressed enough, no desire to repeat) but not enough ego to continue threads like this. |
Hello Ryuji I'm not sure there's any politicizing. I just felt as the designer of what is, I believe, a high performance transceiver, I should explain why L401 was used and why I think it is important for performance reasons. Looking?for disadvantages to a component?omission is a tricky thing, because the circumstances of the tests may not show up the disadvantages. My favourite example is a noisy SMPS power supply putting out wide bands of noise every 50kHz or so. If you happen to have your receiver tuned in between two of these horrificisms, you may well think your SMPS is beautifully quiet, you hear just as well as with a linear regulated power supply. But the circumstances of the test gave the?false result. Meanwhile you'll recommend everyone incorrectly, that particular model of SMPS is very good for radio. It's an innocent error but one I think it helps to look out for. I'm grateful that some others have provided their opinions and real world experiences, the latter being the most valuable?of all.? 73 Hans G0UPL On Wed, Oct 18, 2023 at 3:47?PM Ryuji Suzuki AB1WX <ab1wx@...> wrote:
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On Tue, Oct 17, 2023 at 09:50 PM, Stephan Ahonen KE0WVA wrote:
Well, yes, but this would be because the actual signal entering the radio actually contains that harmonic. Even a sharp bandpass or high pass filter that perfectly isolated the band of interest wouldn't filter this out, because it's a signal, not an artifact. A real AM radio station would not be allowed to generate harmonics so strong that they interfere with the amateur radio band, so if we're interested in the effects of nearby AM radio stations we're really only interested in the consequence of a strong signal at the station's fundamental frequency. I'm interested in seeing if there is a realistic scenario where an out-of-band signal generates an artifact in the band of interest, either in the form of a spurious signal or increased noise floor. The primary goal of my experiment was to see if even a very strong signal in the AM radio band, stronger than anyone could realistically ever expect to see hitting the front end of their radio, resulted in any ill effects. I'm fairly satisfied that between the high pass characteristic of C401/402/404, and the selectivity of the tayloe detector, that L401 and the construction challenges it presents is unnecessary for good performance. I welcome anyone to provide evidence to the contrary. Hello Stephan.? it's absolutely the case that any transmitted harmonics on the receive frequency are not artifacts of the receiver.? What I was trying to express is that the Tayloe mixer/ QSD is (I've read) susceptible to sub-harmonics.? This is reported by the design team of the QRP2004.? Also by IK1ODO, who did some interesting work on QSDs around about the same time. But you're also right, of course, about the harmonics of the NanoVNA - silly of me to suggest it.? And yes, evidence is the thing. 73 Rod necessary for good performance. I welcome anyone to provide evidence to the contrary. |
I see a lot of "I think" in this thread, and not a lot of "I measured," or even "I simulated."
One data point is worth a million "I thinks." I fired the strongest test signal I have access to, directly into my radio, and posted screenshots of the results. I see a lot of people telling me I'm wrong, but very little in the way of explaining why my experiment is not valid or representative. This is not how engineering works. Again, I ask and welcome anyone to post even a single actual data point that would change my mind. |
Hello Stephen By injecting a single signal, you will be able to find out at what signal level the radio overloads. But intermodulation requires at least 2 signals. This is the problem?you are trying to reduce, by installing a band pass filter ahead of the mixer. Say you're listening to a signal on 14023 kHz. A nearby broadcast station is 9MHz say. Does his strong signal intermodulate?with the one you're trying to listen?to, raising the noise floor and reducing your capability to receive the wanted signal on 14023? This?is the issue. Not how well the radio withstands a single strong injected signal. So for this reason I think your experiment is not representative of a real-world situation demonstrating the need (or otherwise) for a BPF.? In reality, the wanted signal on 14023 is one thing. But there are thousands of unwanted signals all around, large and small, kHz away and MHz away and 10's of MHz away. If there is no input BPF then all of that adds up and gets presented to the mixer. Non-linearity in the mixer then causes intermodulation mixing products that can raise your noise floor.? Linas' comments earlier in this thread about a side-by-side comparison between a QCX and a uSDX were extremely relevant. The uSDX was originally based on the QCX. To make it multi-band easily, the band pass filter of the QCX was simply omitted. There are other reasons affecting the performance comparison too, an 8-bit 20MHz CPU with single 10-bit ADC isn't much to implement an SDR, as I heard Guido said himself, it's amazing it works at all! 73 Hans G0UPL On Thu, Oct 19, 2023 at 3:02?AM Stephan Ahonen KE0WVA <stephan.ahonen@...> wrote: I see a lot of "I think" in this thread, and not a lot of "I measured," or even "I simulated." |
Stephan |
Stephan wrote:
This is not how engineering works. Again, I ask and welcome anyone to post even a single actual data point that would change my mind Not how engineering works?? Maybe.? Maybe not.? Generalisations, though, are often wrong. This of course is a discussion forum for the owners and constructors of an increasing number of QRP Labs amateur radio endeavours. The following are relevant excerpts from "The QRP2004 all-band HF Transceiver Designed by the QRP2004 Design Team Alan Rowe M0PUB, Jan Verduyn G0BBL & John Law G8BTR Copyright ? 2004 - 2005 by QRP2004 Design Team QRP2004 Web Site: ????????? " : "The band pass filter board performs a number of very useful functions in the QRP2004. On receive it reduces the amount of wideband noise reaching the mixer, and in particular it attenuates signals from bands below the required signal. This latter point is significant with the Tayloe product detector, because it passes sub-harmonics of the required signal frequency with rather less attenuation than we would ideally like. We measured about 45 - 50dB attenuation of the first sub-harmonic on one of the prototypes, and whilst the filters only improve this by a further 5 ¨C 10dB, it all helps." ... "RX Spurious Responses: although this is not an exhaustive list, the main spurious responses are: 1) the first sub-harmonic of the tuned frequency (e.g. unwanted reception of a strong signal at 3.5MHz signal when tuned to 7.0MHz). Rejection of the first sub-harmonic is about 55 ¨C 60dB. ... " Rod |
On 19/10/2023 07:52, Ted 2E0THH wrote:
way you have titled this topicStefan, I'm questioning the "Zero" because you do not display it. The waterfall and spectrum should show some noise to indicate that there are no signals. Completely black means nothing shows above a certain level. It is very rare not to see some weak traces on a waterfall adjusted for best sensitivity. As Hans and others say, testing a receiver is not simple. One thing that a properly tuned L401 does is help suppress interference from signals 3 times the tuned frequency. The mixer will be about 8dB down on a 3x signal. The LPF will reduce a strong signal quite a lot but testing at that frequency will demonstrate that a tuned L401 circuit helps further.. Actually Zero does not exist, in the beginning there was nothing, then along came a singularity that started it all:-) 73 Alan G4ZFQ |