Thanks Jerry,
I had a load of 2W 51R SMD resistors so using 4 in a series parallel arrangement gave me 8W power handling.
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Another way to do the power calculation is Vpk * Vpk / 100, that's practically mental arithmetic, or if you have a scope that measures the peak to peak voltage Vpp * Vpp / 400.
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This simple little dummy load come peak V measurement come attenuator was the best thing I made to help with testing a QMX.
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Incidentally the 2K5 resistor is 1k0 + 1k5.
