>>>>Ahhh, so thus 50v divided by 3 or 4.... Giving 12.5-16.6V. Got it.?
So it would be OK for 20v IF you had a perfect output load matched to the transistor? Makes sense. Thanks, Gary!?
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No. Don't even go there.
At 20V to get 50W out you would be very close to max Idd.? ?Assume 60% efficient that means
for 50W out you need 83W DC in and your are very close to the 5A peak Idd at 20V.? A pair could
but that tends to push the max Vdd.? To get that power you would also have to exceed max
input power or push very close to it.
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What that means is every margin needed for reliability would be at the edge.
Generally any feedline or antenna fault would kill any try.? Quickly!
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Magical thinking will not make the RD16hhf1 into a RD70HHF (a 70W device)!
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Allison
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