Corrected distance reasoning, the maximum WSPR distance should be half of the circumference with a maximum error of one grid square if both the sending and receiving stations were at the borders of the grid square nearest to each other. Does that sound correct. A bit OT no doubt.
As best I know there is no way for WSPR Spots to calculate long path,
then I suppose WSPR does not represent propagation distance but the
distance between the grid square of the sending and receiving
stations. Maximum WSPR spot distance then is one grid square less (if
the reference point used for the calculation is the centers of the two
grid squares) than half of the circumference along the widest axis,
likely near the equator.
In that case the record distance may be between a WSPR equipped
nautical vessel and any antipodal station along the equator.
As the earth has a "squished spherical shape" is it flat at the
poles :-) ?
Thanks Hans, enjoying the QCX+, and wondering about how many WSPR
stations of your design will contributing to the data collection during
the North American total solar eclipse.
Ron VE8RT
On Wed, 03 Apr 2024 10:03:54 -0700
"Daniel Walter via groups.io" <nm3a@...> wrote:
Actually, you can have about 24,000 miles propagation distance. Long path that's just outside of ground wave and too close for skip.
--
73, Dan? NM3A
--
Ron VE8RT <ve8rt@...>
