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Agilent E4406A Pulling down the power supply not starting


 

I have one E4406A with the same problem. I didn't disassemble it. I saw comments that could be the power source. Do I check the power source directly?
It has the same characteristic sound. And it does the same as the video in these links. Strange that before it was working perfectly.


 

I will tell you the tests I did.
I turned off all the accessories.
I did a good cleaning.
I only left the motherboard with the fan controller.
I replaced all the 100k 1206 and 150k 1206 resistors. Same problem. I measured the old resistors and checked that they were good, and put them back in.
The source LED turns on (green), but I hear a noise when it pulses.
The red LEDs on the fan control board sometimes light up (red) and sometimes not.
Same problem continues.


 

Hi
I'm doing as it says in the manual.


I don't have the tensions. And every time there is a pulse it resets the voltages. Both + and -.


The processor LEDs always blink.


 

Do you have the power supply loaded? Switching supplies often don't
like running at no/reduced load.

-Chuck Harris


On Thu, 11 Apr 2024 13:04:40 -0700 "Jesse Joabe"
<jessejoabe2007@...> wrote:
Hi
I'm doing as it says in the manual.

I don't have the tensions. And every time there is a pulse it resets
the voltages. Both + and -.

The processor LEDs always blink.

Attachments:
dummyfile.0.part:
/g/HP-Agilent-Keysight-equipment/attachment/143385/
dummyfile.1.part:
/g/HP-Agilent-Keysight-equipment/attachment/143385/1
dummyfile.2.part:
/g/HP-Agilent-Keysight-equipment/attachment/143385/2





 

I didn't understand?


 

What didn't you understand? The words, or the concept?

-Chuck Harris


On Thu, 11 Apr 2024 14:30:28 -0700 "Jesse Joabe"
<jessejoabe2007@...> wrote:
I didn't understand





 

Sorry. I use translator. I couldn't understand the words and the concept. Sorry. But I appreciate the help


 

Switching power supplies can not work without enough load.

They go into a cycle where they turn on, and then off.

You need to connect a resistor to their big output that will

load the supply to 1/10th its rated current or more.

-Chuck Harris


On Fri, 12 Apr 2024 03:08:30 -0700 "Jesse Joabe"
<jessejoabe2007@...> wrote:
Sorry. I use translator. I couldn't understand the words and the
concept. Sorry. But I appreciate the help