If I go with what you posted earlier I can assume that your current tank coil has 49 turns on a 31mm OD former using 0.4mm diameter wire (close wound) I can punch these numbers into the software program.?
For 0.4mm enamelled wire I usually assume about 0.06 to 0.08mm is added to the diameter of the wire because of the enamel coating. The enamel coating means the copper itself isn't perfectly close wound.
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So I've set the centre to centre gap of each winding at about 0.46mm in the software program.
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The software then predicts an inductance of about 66uH at 1.45 MHz and a Q of about 125. See the image below.
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This software is based on about 75 year old equations and lookup tables for inductance and Q factor etc. These old equations and tables have been proven many times by lots of people to be reasonably accurate.
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So I would expect your inductor to have an inductance of about 66uH and a Q of about 125 at 1.45 MHz. It shouldn't be far off these numbers unless the former you are using is adversely affecting the coil.
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A Q of 125 isn't that great. It should be possible to achieve a much higher Q if you use thicker wire and change the coil dimensions. This will end up having much larger dimensions than your current coil though. I can show you what I mean using the software if that helps?
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The alternative is to use Litz wire. Something like 160 strands of 48 gauge wire for example. This would give a much higher Q although it won't be cheap to buy Litz wire like this. It might double the Q compared to using a single strand of copper wire of equivalent diameter.
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