Matt's circuit will work very well. The output of this "push pull" circuit is totally identical to using a full bridge rectifier.
Bob Thomas
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--- In CAD_CAM_EDM_DRO@y..., Matt Shaver <mshaver@e...> wrote:
I'm going to assume you want to make a DC supply:
(horrible ascii scematic follows - view in fixed width editor like emacs)
----|>|-----------+
) |
) |
) |
---o MINUS_DC +---o PLUS_DC
) |
) |
) |
----|>|-----------+
Basically, the center tap is the negative pole of the DC supply and the two
ends of the secondary winding are connected to the anodes of two rectifier
diodes. The cathodes of the rectifires are tied together and that is the
positive pole. You could flip both diodes around to reverse the polarity if
you want to...
you'll need a filter cap as well...
Matt
On Wednesday 23 October 2002 02:55 am, you wrote:
I have a transformer that is center tapped on the secondary. Voltage
from the center tap to either end is 30 v. from end to end it is 60
volts. I know that if I want 60 volts I just connect the ends to the
bridge and tape off the center tap. How do I connect it if I want 30
volts at the maximum amperage possible? I realize I can connect from one
end to the center and get the 30 volts, but it seems like I am missing
out on amperage by not somehow using the other half of the coil.
Tim
[Denver, CO]
