¿ªÔÆÌåÓý

Date

Re: Going digital? #ubitx

 

You did not have to use a signal inverter with the easydigi or did you flip it in software?

?

?David


Re: uBITX Display Separation Cable

 

Using old IDE cables is a very good idea.

Note that there are many types of cable available, but most of them will be either
40 wire or 80 wire cables. the difference in the newer (ATA) 80 wire cables is that
every other wire is used to separate and shield the signal wires. All 40 ground wires
will be connected either to the even side or the odd side of the connector, 2 adjacent
wires to each pin.

In the older cables, there is no ground wire; each signal is routed through each of the
40 pins. It will work, but provides no shielding. Note also that he signal path in the
ATA cables has been cut from 40 to 20 wires. That will make little difference to a
lcd connection. The electronic difference is in the interface port.

It is a good idea to use the 80 wire cable and determine which side is ground, and then
connect that side to ground. That will provide shielding for the signal wires and will
cut down on RFI considerably.

Note that these connectors have 2 rows of 20 pins each. You will be connecting 16
pins for a 16x2 display. Usually, also, these connectors have a center connector for
another drive. Cut the cable so that the shortest of the two connectors are at the ends
of it. Note also that the result will usually be a cable with 2 female connectors, so
that you will have to make a sort of adapter to provide the normal M-F ends.

I don't know if all of this information is exactly correct, but I do know that they work very well.

john
AD5YE


Re: uBITx: Encoder without detents

 

Those will work, but the 15mm shaft version is even better!

Thanks Lucian

Mike


On Fri, 12 Jan 2018 at 12:16 PM, Lucian Vittori via Groups.Io <lvittori=[email protected]> wrote:
Would these work?


Re: Going digital? #ubitx

 

Hi,

Just to chime in here:? I used the EASY DIGI and a cheapo USB-to-RS232 I bought at the local electronics store.? Wired everything up in the conventional way, tied the EASY DIGI's PTT-HI to the uBITX mic ring, and its PTT-GND to the uBITX mic ground.? Works fine.

Not that I didn't have technical difficulties, but they were all on the laptop side.? First, the USB RS232 dongle didn't work until I sacrificed several hours to the driver gods.? It's a good thing I had the presence of mind to unit-test that part with a voltmeter before I did anything else.

Next, the laptop failed half the time to detect my audio jack, and the other half the time it sensed the jack but failed to detect any audio.? It turns out that was a simple line-level problem:? if the mic input was too strong, the computer would just assume no valid device was plugged in.? Eventually I learned that I could start the uBITX on the lowest volume level, plug in the audio jack, and raise the volume if necessary; everything would work.

Thanks, Xcott K2CAJ


Re: uBITx: Encoder without detents

 

Would these work?

https://www.mouser.com/productdetail/bourns/pec11l-4020f-s0020?qs=sGAEpiMZZMvy8cVzszrmR8xmhWWclkAFIYEy8Wpdzjs%3D


Re: Raduino 2.02 VFO A/B mode memory

 

¿ªÔÆÌåÓý

Hi Michael


Thanks for the reply. Ok on the next update from Allard. That will be ideal if the mode problem is solved, I will patiently wait until the next release.


Regards

Peter G4NJJ




From: [email protected] <[email protected]> on behalf of Michael Babineau <mbabineau.ve3wmb@...>
Sent: 11 January 2018 19:48:27
To: [email protected]
Subject: Re: [BITX20] Raduino 2.02 VFO A/B mode memory
?
Peter :?

I believe that Allard will be releasing a V2.0.3 load in the not too distant future.
I have been working with him and another list member to Alpha test V2.0.3.?

I believe that the issue you are referring to is fixed. I just tried setting up my VFO A with LSB
and VFO B with USB I am able to TX on either VFO and switch back and forth without any issues
with the mode changing on the VFOs. I am using the V2.0.3 Alpha 2 candidate load.

There was a mode switching problem in V2.0.2 that I reported to Allard and he fixed it.?
Your current problem may be a side effect of the same issue.

Cheers

Michael VE3WMB?


abc's of the si5351

 

Now that I got Han's attention, I'll start a new thread.

> Clockbuilderpro seems to do a massive search for the lowest possible integer values of a,b,c in both PLL and output msynth's
> when I ask for one output of a particular frequency, often leaving both msynths in fractional mode.

Not quite true.?
The output MSynth is as reported, low integers but not in integer mode
on the few random samples I've tried so far.
The PLL MSynth can have fairly large values for B and C, as expected.

Jerry?

######################################################
Hans, on a completely different note, you may find this interesting,
It takes the three si5351 msynth register values for p1, p2, p3 as reported by Clockbuilderpro
and back computes values for a, b, c
Just got it to work this morning, seems right but may yet have issues.

I assume a,b,c must all be integers.
However, a and b could take on fractional values in increments of 1/128 and still yield integer values for p1,p2,p3.
I wonder if that's legal, though not seeing that out of Clockbuilderpro.
Clockbuilderpro seems to do a massive search for the lowest possible integer values of a,b,c in both PLL and output msynth's
when I ask for one output of a particular frequency, often leaving both msynths in fractional mode.
So low integer values are likely the primary way to reduce phase noise.
This is a considerably different approach than all the C code for the si5351 I find out there on the interwebs
Regardless, my guess is that the si5351 has less phase noise in all cases than the typical LC vfo.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char** argv) {
  int  floorg, floorc, ax128, bx128, a, b, c, p1, p2, p3;

  if (argc==4) {
      p1 = atoi(argv[1]);
      p2 = atoi(argv[2]);
      p3 = atoi(argv[3]);
  } else {
      printf("Usage: Takes 3 int args for si5351 msynth reg values p1,p2,p3\n");
      printf("reports int values for a,b,c where a+b/c is the divide ratio\n");
      exit(1);
  }
  printf("  p1:%d  p2:%d  p3:%d \n", p1, p2, p3);
  c = p3;

  // Given an si5351 msynth divide of (a + b/c):
  // p1 = 128*a + Floor(128*b/c) - 512
  // p2 = 128*b - c*Floor(128*b/c)
  // p3 = c			   // All from Silabs AN619
  // Since b<c, Floor(128*b/c) has a value between 0 and 127 inclusive
  // We compute a and b for each of those values, determine which is legal

  for (floorg=0; floorg<128; floorg++) {	// Guess value of Floor(128*b/c)
      ax128 = p1 + 512 - floorg;		// Where ax128 is a*128
      bx128 = p2 + c*floorg;			//  and bx128 is b*128
      floorc = bx128/c;				// Compute value Floor(128*b/c)
      a = ax128/128;  b=bx128/128;
      // Report result if value of Floor(128*b/c) is consistent with guess,
      // and if the computed values for a and b are integers, and b<c.
      if (floorc==floorg && ax128%128==0 && bx128%128==0 && b<c)
          printf("  a:%d b:%d c:%d \n", a, b, c);
  }
  exit(0);
}

Jerry, KE7ER


Re: AE7EU Top Level PCB Mod

 

Also, I wonder if a modular design approach could be used, instead of monolithic. Say a better AGC is devised at some point - how to upgrade/replace it? Same question for the filter banks, what about expanding for additional bands? How about injecting a separate DSP module to the audio chain?

Sorry, just thinking out loud. This design is awesome and has made the wheels upstairs start turning

--
David K4DBZ
Unofficial bitx chatroom:?https://discord.gg/CrHvWFc


Re: AE7EU Top Level PCB Mod

 

Looks pretty awesome!?

Can I recommend using headers for the Teensy?board (as opposed to directly soldering to the board). It adds a little to the cost, but saves headaches down the road when replacing/upgrading the board :)?
--
David K4DBZ
Unofficial bitx chatroom:?https://discord.gg/CrHvWFc


Re: Auto tuner update

 

You are correct, the LFP caps see half of the peak-to-peak voltage, since that RF is centered on ground.

In Farhan's example of 3000 ohms at 10W:
Vrms*Vrms/Ohms = Watts? ? so? ? Vrms = sqrt(Watts * Ohms) = sqrt(3000*10) = 173.2 Volts RMS across the cap
The peak voltage is sqrt(2)=1.414 time the RMS voltage (assuming this is a sine wave halfway through the filter), so 173.2*1.414 = 245 Volts peak to ground.



Hans, on a completely different note, you may find this interesting,
It takes the three si5351 msynth register values for p1, p2, p3 as reported by Clockbuilderpro
and back computes values for a, b, c
Just got it to work this morning, seems right but may yet have issues.

I assume a,b,c must all be integers.
However, a and b could take on fractional values in increments of 1/128 and still yield integer values for p1,p2,p3.
I wonder if that's legal, though not seeing that out of Clockbuilderpro.
Clockbuilderpro seems to do a massive search for the lowest possible integer values of a,b,c in both PLL and output msynth's
when I ask for one output of a particular frequency, often leaving both msynths in fractional mode.
So low integer values are likely the primary way to reduce phase noise.
This is a considerably different approach than all the C code for the si5351 I find out there on the interwebs
Regardless, my guess is that the si5351 has less phase noise in all cases than the typical LC vfo.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char** argv) {
  int  floorg, floorc, ax128, bx128, a, b, c, p1, p2, p3;

  if (argc==4) {
      p1 = atoi(argv[1]);
      p2 = atoi(argv[2]);
      p3 = atoi(argv[3]);
  } else {
      printf("Usage: Takes 3 int args for si5351 msynth reg values p1,p2,p3\n");
      printf("reports int values for a,b,c where a+b/c is the divide ratio\n");
      exit(1);
  }
  printf("  p1:%d  p2:%d  p3:%d \n", p1, p2, p3);
  c = p3;

  // Given an si5351 msynth divide of (a + b/c):
  // p1 = 128*a + Floor(128*b/c) - 512
  // p2 = 128*b - c*Floor(128*b/c)
  // p3 = c			   // All from Silabs AN619
  // Since b<c, Floor(128*b/c) has a value between 0 and 127 inclusive
  // We compute a and b for each of those values, determine which is legal

  for (floorg=0; floorg<128; floorg++) {	// Guess value of Floor(128*b/c)
      ax128 = p1 + 512 - floorg;		// Where ax128 is a*128
      bx128 = p2 + c*floorg;			//  and bx128 is b*128
      floorc = bx128/c;				// Compute value Floor(128*b/c)
      a = ax128/128;  b=bx128/128;
      // Report result if value of Floor(128*b/c) is consistent with guess,
      // and if the computed values for a and b are integers, and b<c.
      if (floorc==floorg && ax128%128==0 && bx128%128==0 && b<c)
          printf("  a:%d b:%d c:%d \n", a, b, c);
  }
  exit(0);
}

Jerry, KE7ER


On Thu, Jan 11, 2018 at 12:39 pm, Hans Summers wrote:
An interesting question. In the LPF, does the capacitor see the peak-peak voltage? It is connected to ground. So, doesn't that mean it sees the peak voltage (1/2 the peak-peak)?
?


encoder interrupt readme file update

Rod Self
 

Hi All,

the encoder readme file has been updated to note 100 nf capacitors from each encoder contact to ground.

New file attached.

Rod KM6SN


Re: Auto tuner update

 

Farhan

An interesting question. In the LPF, does the capacitor see the peak-peak voltage? It is connected to ground. So, doesn't that mean it sees the peak voltage (1/2 the peak-peak)?

73 Hans G0UPL


Re: Auto tuner update

 

¿ªÔÆÌåÓý

Han's, Thanks for a definitive statement.


A selection of filters and a nice relay switch double sided daughter board would have being nice and I wasn't expecting to be able to use yours for circa 40 watts.

I'll plagiarise another design and make do with vero... :-[

Alan


On 11/01/2018 19:01, Hans Summers wrote:

The QRP Labs kit ordering page says 5W. In fact I believe they are fine for at least 10W and this is noted on the LPF Kit page

10W is well within the specified ratings of the cores according to the original G-QRP club website article (see for PDF of the article). 10W is also well within the voltage ratings of the NP0/C0G low-loss RF capacitors used in the LPF kits.

It may be possible to push it beyond 10W. Tolerance of SWR mismatch would be reduced (and eventually disappear). Another factor is component tolerances and winding differences resulting in variation in inductance values. If the filter starts producing attenuation at frequencies lower than it should... i.e. at the transmit frequency - then remember that attenuation means reduction in output power. The reduced power has to go *somewhere* and in fact it is likely to be largely dissipated as heat in the LPF components.?

I'm not sure how far beyond 10W would be Ok before generating smoke. Anyone who has these QRP Labs 7-element (3 inductors, 4 capacitors) filters on their tiny 1.5 x 0.5 inches board (37 x 13mm) would intuitively not think it right to put 100W through it. Even if everything measured perfectly I wouldn't want to go anywhere near 100W!

A confession... during PA development of the QRP Labs 5W HF PA kit (Class C) , I did put 30W continuous keyed through a QRP Labs LPF kit... No smoke ;-)

73 Hans G0UPL?
?


Re: 630 M

 

Should work, Fred. See what I did with QRP Labs filters in the Multi-Band BITX40 link in my signature below. It works very well down to 80m and I'd love to see what you do for 630m. I'd like to try 630m and 2200m as well but alas I have no room for such an antenna!?

--
Ryan Flowers - W7RLF



encoder interrupt software example

Rod Self
 

Hi ALL


I put encoder interrupt code on github at



There is a readme.docx that gives an overview.

The code is a hacked subset of a large project, so there are "leftovers" therein that are not important.

readme file attached here for your convenience.

Rod


Bitx40/Raduino bias help

 

I have a new BitX40 that I am testing on the bench before building it into a case. Right now, it is all stock and I am just testing transmit audio to see how it might be improved. I can receive my signal on a nearby receiver if both are connected to antennas, and hear no distortion or carrier in the signal. In fact, it sounds pretty much like other BitX's I have spoken to on the air with little audio above 1700Hz. However, I cannot hear it at all if it is connected to a dummy load, which led me to measure current draws with the idea I could get an idea of power out with various mic options. I see 0.185amps on receive, and 0.40amp when the PTT is keyed...but it does NOT change when I speak into the mic, no matter how loud I am. I am already past the current draw suggested in the BitX alignment instructions...which I assume must refer to the unit without the Raduino. Should I be playing around with the RV136 in an attempt to see some change when the unit is modulated, or is something else wrong here?

=Vic=


Re: Micro-BITX ... Lost in post ? Possibly

 

Mine arrived today too!


You just got to find the inner strength to wait!


73 Steve


Re: Raduino 2.02 VFO A/B mode memory

 

Peter :?

I believe that Allard will be releasing a V2.0.3 load in the not too distant future.
I have been working with him and another list member to Alpha test V2.0.3.?

I believe that the issue you are referring to is fixed. I just tried setting up my VFO A with LSB
and VFO B with USB I am able to TX on either VFO and switch back and forth without any issues
with the mode changing on the VFOs. I am using the V2.0.3 Alpha 2 candidate load.

There was a mode switching problem in V2.0.2 that I reported to Allard and he fixed it.?
Your current problem may be a side effect of the same issue.

Cheers

Michael VE3WMB?


Re: Micro-BITX ... Lost in post ? Possibly

philip yates
 

Not long got home, and opened the box.?
Now to start the process of working out enclosure sizes, layout etc.
Need to get it up and running first tho.

Mines F37/1, so an early one in the first batch, looks good.

Phil - G7BZD


On Thu, Jan 11, 2018 at 7:39 PM, Charlie Morrison <charlie@...> wrote:

And Mine J

?

Red collection card in letterbox when I got home from work¡­now wheres the soldering iron?

?

Charlie GI4FUE

?

From: [email protected] [mailto:[email protected]] On Behalf Of philip yates
Sent: 11 January 2018 10:39
To: [email protected]
Subject: Re: [BITX20] Micro-BITX ... Lost in post ? Possibly

?

And mine, just arrived

?

Phil -G7BZD

Sent from my iPhone


On 11 Jan 2018, at 10:37, David Holland <g4ldt@...> wrote:

Mine arrived this morning with no updates on either India post or royal mail tracking sites!? Ordered on 9th December - In the notorious "bag" at Mumbai airport on the 15th.? So there is hope yet all you G stations waiting.? By the way my board is marked 71/1 whatever that means.

David G4LDT

?

On 11/01/2018 08:56, Andy Robins wrote:

That's fine if you are not in the UK. But here using DHL will mean paying import charges of 20% plus about ?12 admin fee. I went with India Post and no additional charges were made. Just a warning to my fellow brits.?

?

?

Virus-free.



Re: Auto tuner update

 

The auto tuner capacitors have to be rated for the highest voltage at the highest impedance. This is an extreme requirement. To illustrate, a 10 watt RF signal will put out a peak 30v across a 50 ohms load. However, an end-fed half wave will exhibit about 3000 ohms impedance. At 10 watts, this amounts to a voltahe peak of 250 v. You have to choose the capacitors for 250v rating even for a QRP power level.
- f


On 12 Jan 2018 12:32 am, "Hans Summers" <hans.summers@...> wrote:
The QRP Labs kit ordering page says 5W. In fact I believe they are fine for at least 10W and this is noted on the LPF Kit page

10W is well within the specified ratings of the cores according to the original G-QRP club website article (see for PDF of the article). 10W is also well within the voltage ratings of the NP0/C0G low-loss RF capacitors used in the LPF kits.

It may be possible to push it beyond 10W. Tolerance of SWR mismatch would be reduced (and eventually disappear). Another factor is component tolerances and winding differences resulting in variation in inductance values. If the filter starts producing attenuation at frequencies lower than it should... i.e. at the transmit frequency - then remember that attenuation means reduction in output power. The reduced power has to go *somewhere* and in fact it is likely to be largely dissipated as heat in the LPF components.?

I'm not sure how far beyond 10W would be Ok before generating smoke. Anyone who has these QRP Labs 7-element (3 inductors, 4 capacitors) filters on their tiny 1.5 x 0.5 inches board (37 x 13mm) would intuitively not think it right to put 100W through it. Even if everything measured perfectly I wouldn't want to go anywhere near 100W!

A confession... during PA development of the QRP Labs 5W HF PA kit (Class C) , I did put 30W continuous keyed through a QRP Labs LPF kit... No smoke ;-)

73 Hans G0UPL?
?