On the contrary.
These? are voltage devices, not current devices. If you put enough voltage on the gate, it will go into avalanche mode and destroy the device within milliseconds. Always start with noting the gate voltage, and NEVER exceed 5v. DC.? Even this is questionable since there is a lot of variance in these devices and the gate voltage is not a fixed amount.
As to AC voltage, mostly you are looking for the instantaneous quantity. That can and will easily exceed 5v. But it must never remain there for more than a microsecond or two for the reasons above.
The 50 ma. figure is an assumption that this will put the device in the more or less "safe" zone. That is not guaranteed. With your device, 50 ma. gives you a gate voltage of ~3.5v, but that is not fixed. Every IRF510 (every switching MOSFET for that matter) is different. If the average "good" voltage is about 3.5-4.0v, then about half will be lower than that; half slightly more than that, but never more than 5v or so.
john
AD5YE
---In BITX20@..., <socijalizam1@...> wrote :
you must look the current ,about 50ma (witahout input signal) ..voltage is not imporant but in my case is 3,4v on gate irf 510
