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Re: Bitx 40 board.


 

Yes John.?? Think of a 300 Hz tone and a 3000 Hz tone going into a balanced modulator producing a Double Sideband signal.

The balanced modulator produces sum and difference frequencies.

With the carrier at 7.2 MHz: ?

On the upper (sum) side:? 300Hz?= 7.2003? while 3000Hz = 7.203

On the lower (difference) side? 300 Hz =7.1997??????? 3000 Hz = 7.197

Think of the audio producing symmetrical (but?mirror image) sidebands around the carrier with the lower frequency audio tones producing sideband signals closer in and higher frequency audio tones producing sidebands farther out from the carrier.?

We use a filter (most of the time) to select one or the other.

This is not "sideband inversion"?? This is just the way modulation works.

Sideband inversion happens when you take one of those sidebands and?-- in a mixer -- subtract it from a local oscillator (VFO).???In that case what had?been an LSB signal becomes a USB signal.? And you must then place your BFO signal accordingly.

Does that make sense?

73? Bill N2CQR ?


On Saturday, December 24, 2016 8:00 PM, "iam74@... [BITX20]" wrote:


?
"7.1997 corresponds to the 300Hz audio, 7.197(0) corresponds to the 3000Hz audio"

Really? Is a SSB LSB RF signal coming in with the audio inverted? It certainly is not coming from the IF that way.

If inversion happens, it must happen twice (or an even number of times) for it to be readable.

john
AD5YE


---In BITX20@..., wrote :

Ken:?? I think?sideband inversion is a lot simpler than that and can easily be explained without resort to "negative frequencies."
Just consider an LSB signal coming in at 7.2 MHz.? It will be spread out from about 7.1997 down to? 7.197 Mhz.? 7.1997 corresponds to the 300Hz audio, 7.197 corresponds to the 3000Hz audio.
Assume your IF and crystal filter ate at or around 10 MHz.
You have two options for the VFO:? 2.8 MHz?or 17.2 MHz.
With 2.8 MHz you take the sum product out of the mixer.?7.1997+2.800=9999.7 MHz?? 7.197+2.800=9997? That's an LSB signal at 10 Mz. NO INVERSION
With 17.2 MHz you take the difference: 17.2-7.1997+10.003MHz????? 17.2-7.197+10.003 MHz..? That is a USB signal at 10 MHz? SIDEBAND INVERSION!
It helps to draw this all out.? See attached.?
This proves the rule:? Sideband inversion only takes place when you SUBTRACT the signal carrying the modulation FROM the signal without the modulation (the VFO or LO).
Please let me know what you think about this explanation.?
73? Bill N2CQR




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