Re: XEphem 4.2.0 has been released
Hi Brandon and Elwood,
I'd like to join in on the chorus of people thanking you for keeping this software package alive. I had recently reformatted my computer, and after seeing this release
By
Rick Towns
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#4062
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Re: XEphem 4.2.0 has been released
Thank you Brandon and Elwood! I compiled and installed this new version of xephem the same day was released. From 1996 I have been doing this with every version. The new 4.2.0 release comes to
By
Emilio Ortiz Linux
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#4061
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Re: XEphem 4.2.0 has been released
"Brandon Rhodes" <brandon@...> wrote:
Thanks for keeping this venerable software alive! It was one of the
first software packatges I compiled for X Windows back in 1991 or so
on a Sun
By
Joe Hartley
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#4060
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Re: XEphem 4.2.0 has been released
Thank you Brandon and Elwood!, this new release brings a new life for all of us!I will install on my FreeBSD 14.0 Box right away!
Greetings from M¨¦rida, Yucat¨¢n, M¨¦xico, The Maya Land!
Eric.
By
Eric De La Cruz Lugo
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#4059
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Re: XEphem 4.2.0 has been released
Thank you very much for the new release, Brandon!
And many congratulations on the new version. :)
--
With best regards, Alexander
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Alexander Wolf
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#4058
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Re: XEphem 4.2.0 has been released
Thanks so much, Brandon.
Bernie
NASA/IRTF
By
Bernie Walp
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#4057
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Re: XEphem 4.2.0 has been released
Thanks Brandon,
It's nice to see official releases again for this great software.
Your efforts are appreciated!
Don
By
Don Stalkowski
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#4056
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Re: XEphem 4.2.0 has been released
Many thanks to Brandon for his excellent stewardship and to everyone for
their valuable contributions. Long live XEphem!
Elwood
wrote:
By
Elwood Downey
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#4055
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XEphem 4.2.0 has been released
I have just released XEphem 4.2.0.
https://github.com/XEphem/XEphem/releases/tag/4.2.0
The change log:
- Elwood himself has contributed a new option that lets you switch
XEphem from giving
By
Brandon Rhodes
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#4054
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Re: Estimating Mars orbital period from simulated ground-based observations?
Dear Elio,
Thank you again for your advice!
Yours,
Maxime
--
Maxime GOMMEAUX, ma?tre de conf¨¦rences
- Affiliation:
Universit¨¦ de Reims Champagne-Arden
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Maxime GOMMEAUX
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#4053
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Re: Estimating Mars orbital period from simulated ground-based observations?
I agree with you. I have not xephem installed and cannot verify, but apparently EcLong is what I named geocentric ecliptic longitude.
Of course EcLong is more strictly related with observations made
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Elio Fabri
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#4052
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Re: Estimating Mars orbital period from simulated ground-based observations?
Dear Elio,
Thank you for putting me on the right track!
I can't see on XEphem the exact "geocentric longitude" that you mention but in Data Table, I can display the heliocentric latitude/longitude
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Maxime GOMMEAUX
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#4051
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Re: Estimating Mars orbital period from simulated ground-based observations?
of Mars using only data from XEphem-simulated ground-based observations. I mean, from Sky view, from the Data table... and of course not from the Solar system view.
I have not being using xephem for
By
Elio Fabri
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#4050
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Estimating Mars orbital period from simulated ground-based observations?
Dear friends of XEphem,
I would like to have my Bachelor students estimate the orbital period of Mars using only data from XEphem-simulated ground-based observations. I mean, from Sky view, from the
By
Maxime GOMMEAUX
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#4049
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Sun, rising and setting times
Hello,
I have few questions about the settings to compare ephemeris generated by XEphem and almanac data.
Times are calculated for upper limb or sun center crossing the horizon?
Atmosphere pressure: 0
By
[email protected]
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#4048
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Re: Moon phases,solver
Thanks to all have contributed to help me visualize why the moon elongation from the sun is only rarely approaching 0 or 180 degrees.
stefano
By
[email protected]
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#4047
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Re: Moon phases,solver
I will not go beyond your first line.
First, the ecliptic is not a plane.
Neither it is Earth's orbit, as some believe.
The ecliptic is a great circle on the celestial sphere.
From a geocentric point
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Elio Fabri
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#4046
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Re: Moon phases,solver
It is true that, on new moon, the projection of the Sun-Earth-Moon angle is
zero, but I think that the elongation is defined as the actual angle, not
the projected angle.
The elongation will be zero
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Tomas L. Gomez
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#4045
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Re: Moon phases,solver
The ecliptic is the "mean invariant plane" of the solar system.
The solar system consists of the Sun, Jupiter and other debris!
So the Earth can be slightly above/below the mean plane (timescales
on
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Wayne Green
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#4044
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Re: Moon phases,solver
My astronomy professor did quite well with a rubber ball and a flashlight,
but try Wikipedia. I wrote a program showing how it works once.
<s.bortolussi@...> wrote:
By
ab1jx
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#4043
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