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So, the match is good over HF. Thinking after I hit send: Why not connect the secondaries together as you did for the S11 measurement and do an S21 measurement to assess loss? That way, both ports are

Looks pretty darn good to me. However, I must pose the question: how much of that good-looking SWR and centered on the Smith Chart is due to loss? Dave - W?LEV -- *Dave - W?LEV* *Just Let Darwin

On a NanoVNA-H, a linear polarizer, like most polarized sunglasses, has relatively little affect on intensity, regardless of the orientation. But in conjunction with pair of "3D" glasses, crossed with

Kerr, Here are some tests I did with 1 full turn on primary with 5 full turns on secondary. Primary wire comes out one side and secondary out the other. Ratio of 5 turns gives impedance transformation

I have removed the two transformers from my test circuit and attached the NanoVNA to the primary of the first one, the two transformers secondaries (8 turns) are connected together and a 50 ohm

Physically, yes. Circuit-wise and considering magnetics, its is a full turn. Dave - W?LEV wrote: -- *Dave - W?LEV* *Just Let Darwin Work* *Just Think*

I will try this now and see what it looks like.

Hi Roger, When I do one full turn on the primary (through the first hole and back down the second) I get the results as shown in the attached images. This is why I removed part of a turn to see what

Kerr, Here is a link with actual tests of transformers made with 73-202 binocular cores. Make sure you use insulated wire because 73 Mix material has low resistivity compare to Mix 43.

Kerr, Something is off with your results. I don't know how you are winding the binocular cores. You need full turns and one turn is a complete loop through one hole and back again. Try measuring VSWR

Ok, understood, but a picture would help to clarify it. -- El software de antivirus Avast ha analizado este correo electrónico en busca de virus. https://www.avast.com/antivirus

The BN cores aren't actually toroids, they are "balun" cores or "binocular" cores that have two holes through them. So, if you wind through only one hole, you have a half turn.

Thanks, this is what I was trying to figure out. And thanks for those files! -- KV0A - Robert

hi Kerr, I really don't understand the 0.5 to 8 ratio and the "full turn" comment. In toroidal cores, one pass through the hole counts as a full turn, there are not things as half turns, so probably

To this reply I have attached the images from my NanoVNA, there are two VSWR plots and two smith chart plots. When using the FT37-43 toroids on the input and output I get about a 1.58 to 1 VSWR at

I have received my new toroids (BN-73-202) and have been having a look at the difference between them and my FT37-43 ones. In this reply I have attached three images. The first is the NE602 with an

Well, I think that the right number is? 1000000 or 1E6 Regards, Ignacio EB4APL -- El software de antivirus Avast ha analizado este correo electrónico en busca de virus.

Thank you Herb! I've made note of your instructions. Rick

Dear Luc, Before, congratulations for this nice presentation. On page 52 (TDR measurement), there is a small typo error with the example in the formula. With 1 MHz frequency step, divider must be

On Mon, Mar 16, 2020 at 06:37 PM, Hernán Freschi wrote: Hmm that seemed to work! I wonder why? ============================================= Hernán, That shows that your cable is o.k., CH0 is