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Re: anti-stati foam sheets for lining case
On 6/28/21 12:07 PM, Bill Higdon via groups.io wrote:
I might use one of the anti static envelopes I have as an added feature. I can see for what JPL is involved with any particle shedding causing issues. But with my experience with the pink foam in other applications it didn't cause any problems.Just in case, it's not a concern about "space hardware" per se, it's the particles and coating from the sheet material the pink poly bags are made from getting into the electronics and causing "mystery not quite shorts". The containment of "foam falling apart" is just gravy. |
Re: RETURN LOSS thoughts de k3eui
You've received many good replies, but I can't help to contribute mine as
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well, so: Quote: " So the FORWARD voltage is always positive and the RETURN signal is attenuated.." But if all we measure is voltage, it well could be static with no real power involved. A charged cloud may be at a high voltage, but nothing happened unless a lightning discharge occurs. Current flows from the cloud to earth or to another cloud. That current produces all kinds of electromagnetic energy. If we have just voltage on the transmission line, no power is conveyed. Just voltage alone is inadequate to measure the flow of RF energy. Both voltage AND current are required. S-Parameters are truly a measure of vector power - both voltage and curent. Dave - W?LEV On Mon, Jun 28, 2021 at 6:13 AM Barry K3EUI <k3euibarry@...> wrote:
I have been wondering for months why I object to RETURN LOSS being a --
*Dave - W?LEV* *Just Let Darwin Work* |
Re: RETURN LOSS thoughts de k3eui
On 6/28/21 8:24 AM, Maynard Wright, P. E., W6PAP wrote:
Carey, On the other hand, if someone quotes a Return Loss as either positive or negative, the *meaning* is generally understood, unless the circuit returns more power than it receives (a ferrite circulator with an amplifier, perhaps).? So beating someone up for choosing the "other" convention probably isn't worth it.? If you're publishing a paper, or better, writing a procurement spec or test procedure) - make sure it's right.? In the latter situations, I tend to not use the term return loss, rather, I'd specify |S11| < -10 dB. |
Re: I/O RF Matching net-works measuring with NANO-VNA
#applications
On Mon, Jun 28, 2021 at 08:52 AM, Peter wrote:
I was asking WHY the INPUT Resonance changed as soon as I apply Power-SupplyWhen you apply bias to the transistors Q1 and Q2 the input impedance looking into the base of the transistors changes. This affects the overall input impedance of the network (including any observed resonances) seen at the junction of the 1 nF and 120 pF capacitors. The semi-rigid coax is attached at this point so the impedance seen at the input to this coax will also change. The input resonant circuit formed by the 47 ohm resistor, 330 nH inductor, 220 pF cap, 47 pF cap in parallel with this coax input impedance will now have a different resonant frequency. Roger |
Re: Firmware version 1.0.39
Art, if you're using defuse to update the software, read my post several messages back.?
Defuse uses confusing terms. Upload means to copy from the device to the PC.? Read my post and install the modified defuse I made, then delete the firmware file you've been trying to install and download and install a new copy.? On Mon., 28 Jun. 2021 at 10:45 a.m., aparrisjr@...<aparrisjr@...> wrote: I reloaded thee software and it shows the device. I uploaded the new firmware and the program shows device 00 updated and the screen shot is like the one you provided. When I check the firmware version on the Nano it is still 1.0.39. I tried the another version with the same results. Thanks for your help. Art |
Re: RETURN LOSS thoughts de k3eui
On Mon, Jun 28, 2021 at 05:13 AM, Barry K3EUI wrote:
We had a topic on this subject a few months ago. I posted a link to a paper by an IEEE editor on the "Definition and Misuse of Return Loss" which details the history and why it is a positive number. It makes for interesting reading. /g/nanovna-users/message/18708?p=,,,20,0,0,0::Created,,IEEE,20,2,0,78100772 Roger |
Re: I/O RF Matching net-works measuring with NANO-VNA
#applications
Hi William ... of course the "squared BIAS" I Drawn is just the one made with the BY1-1F ... there is no any other Bias ...
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I was asking WHY the INPUT Resonance changed as soon as I apply Power-Supply (and consequentely the Bias) .... I was just a question ... Peter. ----- Original Message -----
From: "William Smith" <w_smith@...> To: <[email protected]> Sent: Monday, June 28, 2021 5:46 PM Subject: Re: [nanovna-users] I/O RF Matching net-works measuring with NANO-VNA #applications Aside: not sure why you are biasing the input, looks like the transistors are already biased on thru BYI-1F, and the input is capacitively coupled. At the very least the B-E junction of a transistor changes its¡¯ capacitance when you bias it on, no? William Smith ComputerSmiths Consulting, Inc. w_smith@... On Jun 28, 2021, at 9:57 AM, Peter <yliroma@...> wrote: |
Re: I/O RF Matching net-works measuring with NANO-VNA
#applications
William Smith
Aside: not sure why you are biasing the input, looks like the transistors are already biased on thru BYI-1F, and the input is capacitively coupled.
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At the very least the B-E junction of a transistor changes its¡¯ capacitance when you bias it on, no? William Smith ComputerSmiths Consulting, Inc. w_smith@... On Jun 28, 2021, at 9:57 AM, Peter <yliroma@...> wrote: |
Re: RETURN LOSS thoughts de k3eui
Carey,
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You are exactly right.? Terms such as "return loss," "reflection loss," "reflection coefficient," "SWR," etc. all have precise meanings that are very important.? Many of them are defined in IEEE, ITU, and/or ANSI standards.?? Telephone engineers who work on voice frequency or low carrier frequency cable pairs, incidentally, generally work in terms of return loss and reflection loss rather than reflection coefficient and SWR because the last two measures are not easy to work with when the characteristic impedance is complex rather than approximately real. And be careful about the assumptions that are made for RF calculations above a few hundred kHz.? For purposes of the characteristic impedance, the primary constants G and R and usually assumed to be zero so that the resulting calculation of Zo is real. But a seemingly contradictory assumption is made for the complex propagation constant, where calculation of the attenuation is important.? For that calculation, G is usually assumed to be zero, but R, L, and C are not.? It makes sense to do it that way, but it has proved confusing in some contexts. Maynard Wright, W6PAP On 6/28/21 6:45 AM, Carey Fisher wrote:
The term "Return Loss" wasn't invented yesterday. It's an engineering term |
Re: Firmware version 1.0.39
I reloaded thee software and it shows the device. I uploaded the new firmware and the program shows device 00 updated and the screen shot is like the one you provided. When I check the firmware version on the Nano it is still 1.0.39. I tried the another version with the same results.
Thanks for your help. Art |
Re: VNA shootout
On Sun, 27 Jun 2021 at 20:22, Donald S Brant Jr <dsbrantjr@...> wrote:
Jim: The optimal way would be to measure several standard articles on eachI'm not convinced that tells you anything useful, unless one is known to be good. A lot of these VNAs are copying code from another, so I would not trust that. The classical verification/transfer standards are a Beatty mismatch standard which is a section of 25¦¸ air line between 50¦¸ air line sections, My company produces kits with one verification attenuator. It is not as good as a Beatty line, or airline, but it produces something that can be verified. One customer with an R&S VNA got very different results on the attenuator to those we supplied. Yes, I once demonstrated to someone that a 22 ohm wire-wound resistor could be used as a calibration standard. If that's defined to be 50 ohm in the calibration routines, then it will show a very high return loss if you measure that same 22-ohm wire-wound resistor. If you then connect a high quality 50 ohm load, it will look awful. I have found that measuring a filter with passband and stopband within the calibrated frequency range as a quick check gives pretty useful informationMETAS have published a lot on that, as have NPL. 73, Don N2VGU. Dr David Kirkby Ph.D C.Eng MIET Email: drkirkby@... Web: Kirkby Microwave Ltd (Tel 01621-680100 / +44 1621-680100) Stokes Hall Lodge, Burnham Rd, Chelmsford, Essex, CM3 6DT. |
Re: I/O RF Matching net-works measuring with NANO-VNA
#applications
Thanks to eveyone gave an answer ...
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Of course I realize the Bias is affecting the Input (and output) impedance of any device ... BUT WHY ??? I intend to highlight my P.A. is a A/B Class RF Amplifier equipeb by two parallele transistor coupled somehow: Attached the schematics : it is a surplus (ex milititary) unit which was working originally in AM mode ... the related Bias is obtained via a paritcular DIODE ... For those who think DC Power-Supply introduces some extra impedance: this not true .. all +Vcc Supply lines are grounded by the CPs capacitors and RF is blocked by the JAFs... See the attached schematics. At any rate I have to connect my NANO-VNA when the system is Power-supplied ... ISN'T IT ??? Peter ----- Original Message -----
From: "schweppe" <schweppe@...> To: <[email protected]> Sent: Monday, June 28, 2021 1:38 PM Subject: Re: [nanovna-users] I/O RF Matching net-works measuring with NANO-VNA #applications Hi Peter, |
Re: RETURN LOSS thoughts de k3eui
The term "Return Loss" wasn't invented yesterday. It's an engineering term
that's been around for decades. It's just like the concept that electrical current flows from positive to negative. These are conventions that help everyone understand things from the same reference point. 73, Carey, WB4HXE On Mon, Jun 28, 2021 at 8:36 AM William Smith <w_smith@...> wrote: Well, since you are being pedantic (don't get me wrong, I like pedantic,-- Carey Fisher careyfisher@... |
Re: I/O RF Matching net-works measuring with NANO-VNA
#applications
On 6/28/21 5:43 AM, G8DQX list wrote:
Peter,If it breaks into oscillation (or picks up a spurious signal) it could easily push more than 10dBm *out* of the input port. Even operating as designed, it could have surprisingly high power coming out the input. In order to be stable, the S12 (reverse isolation) just has to be bigger than the forward gain (S21) (slight oversimplification). Let's say the amplifier gain is 10 dB,? S12 is -15 dB, and a mismatched load reflects -20dB, and the amplifier is putting out 100W (+50dBm) - the reflected power from the load is +30dBm, the amplifier (going backwards) reduces that to +15dBm. |
Re: I/O RF Matching net-works measuring with NANO-VNA
#applications
Peter,
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you haven't indicated whether the amplifier is linear (class A or AB or B) or class C (for FM or CW). The circuit operating conditions (class, signal level, bias, Vcc) make a big difference. Input match The input match is generally designed to present 50¦¸ to the input socket. Output match The output match is generally designed to deliver maximum power to a 50¦¸ load. The PA is *not* a conjugate match, which would reduce the output power by 6dB! Take care A nanoVNA (most VNAs for that matter) is not safe anywhere near a 200W amplifier. All it would take is a spurious oscillation in the PA, and the VNA is likely to see rather more than +10dBm (10mW) at a measuring port, with the danger of damaging the VNA electronics. (See also /g/nanovna-users/topic/77980973#18555 </g/nanovna-users/topic/77980973#18555>, for instance.) HTH, 73, Stay Safe, Robin, G8DQX On 28/06/2021 12:38, schweppe wrote:
Hi Peter, |
Re: RETURN LOSS thoughts de k3eui
William Smith
Well, since you are being pedantic (don't get me wrong, I like pedantic, it helps add clarity and reduce confusion):
On Jun 28, 2021, at 8:13 AM, Barry K3EUI <k3euibarry@...> wrote: RL is positive - You "lose" 20 dB or whatever.Exactly So now the RETURN signal is attenuated by -X dB.Now you've got it backwards again. Return signal is attenuated by some number of dB, but that number (the amount that it's attenuated) is a positive number. You should say "So now the RETURN signal is attenuated by X dB." You wouldn't say "I drove 20 miles, now my gas tank has been emptied by MINUS one gallon", would you? You would say "I'm down one gallon" or, (if you really wanted to be confusing) "I'm up by MINUS one gallon". So why is it called RETURN "loss" ?Because I sent a signal into the device, and some amount of it returned. And (usually) the amount that returned is LESS than the amount I sent, so: GAIN of the device (how much MORE I got back compared to how much I sent) is less than one (a negative number). LOSS of the device (how much LESS I got back compared to how much I sent) is a positive number. Think of measuring through a passive network, your gain is negative, but your loss is positive. Does that help? 73, Willie N1JBJ [Yes, I have the T-shirt: "Does Anal-Retentive have a hyphen?"] |
RETURN LOSS thoughts de k3eui
I have been wondering for months why I object to RETURN LOSS being a "positive value".
Yes, we are talking about a LOSS. And of course the formula shows RL = -20 log (rho) Since rho is a number between zero and one, the log (rho) is itself a negative number. And -20 times a negative number is positive. OK OK.... I get the math. RL is positive - You "lose" 20 dB or whatever. Now, what if we just rename the term to RETURN voltage (drop the "loss" in the label). The return voltage is less than the forward voltage. I hope that is true. So now the RETURN signal is attenuated by -X dB. Now that feels right. It's the word "loss" in RETURN LOSS that makes it confusing (I'm not an engineer). So the FORWARD voltage is always positive and the RETURN signal is attenuated..... Now I can say correctly that the reflected signal is - 10 dB compared to the forward signal. In fact, that's the way I think of it, even if I don't say those words. When I plot SWR of an antenna, the low numbers (close to 1) are "good". Bad numbers for SWR are 3 and above. When I plot the RETURN voltage on the same antenna, it feels that a DIP (negative number) is also good, in the sense that the graphs have the same overall shape. Why is that pleasing? Or is this just a play on words? It's not a big deal, as long as we realize what the graph means. I want a low SWR. I want a big return loss (I want no return signal at all if possible). If my antenna-feed line match is good, there is very little power returning to the source. So why is it called RETURN "loss" ? de k3eui Barry |
Re: I/O RF Matching net-works measuring with NANO-VNA
#applications
Hi Peter,
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every amplifier (Transistor or Tube) will change its input (and output) impedance due to bias. So input (and output) impedance of impeadance matching network as shown in your picture will also change when bias to the amplifier is supplied. 73, Guenter, DK5DN Am 28.06.2021 um 10:02 schrieb Peter: Hi there ... |
Re: I/O RF Matching net-works measuring with NANO-VNA
#applications
William Smith
Sure, a couple of possibilities:
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1) When your power supply is off it's a high impedance, and when it's on it's a low impedance, so you are at the very least switching in another inductor. 2) Semiconductor junction capacitance depends on applied voltage, and there are semiconductors in the amplifier block. 3) Your amplifier block is accepting input power (to amplify it) or not. You could think of this as an additonal load. Without more details we can only speculate, but I'm not surprised at your results. I would certainly expect the input of the amplifier to change when it's powered up. 73, Willie N1JBJ On Jun 28, 2021, at 4:02 AM, Peter <yliroma@...> wrote: |
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