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Hi Everyone,
Could anybody tell me a way I can pull voltage from the board for an LED on RX and then pull voltage from the board for a TX LED and turn off the RX LED?
Thanks Ben KD2NOU --
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Just go to the Rx and
Tx lines that control the direction of the amps.? Put a 1K to
each Led from them.
I think that is what
you asked?
73's
Mike, WA6ISP
On 11/5/2017 1:20 PM, Ben Piecora
wrote:
Hi Everyone,
Could anybody tell me a way I can pull voltage
from the board for an LED on RX and then pull voltage from the
board for a TX LED and turn off the RX LED?
Thanks
Ben
KD2NOU
--
--
Mike Hagen, WA6ISP
10917 Bryant Street
Yucaipa, Ca. 92399
(909) 918-0058
PayPal ID "MotDog@..."
Mike@...
|
Easy, Ben! Consult the circuit diagram. Relay K1 is supplied with +12V. It then feeds either +RX or +TX as the case may be. The underside of the board has the pads to connect to, either to individual LEDs with series resistors to 0V or to a 'bi-color' LED with resistor from its common lead to 0V. Those voltages can be accessed on the top side of the board by locating resistors in the 'bi-amp' section/s and carefully attaching your wires. The traces there follow the circuit diagram. A little mental effort, but well worth it. I'd suggest only a TX LED - if not lit, the rig is is Rx mode. If your kit is non-Raduino, I'd suggest a 'Power on' rather than 'Rx' LED.
73
Dex, ZL2DEX
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Mike beat me to it, and with better. Resistor first, then wire to diode/s (raw voltage to flying leads not the best idea! :)
73!
|
If 12V, maybe go to
3.3 to 4.7K.? Leds are fairly bright at a couple of ma?
Mike
On 11/5/2017 2:33 PM, Dexter N Muir
wrote:
Mike beat me to
it, and with better. Resistor first, then wire to diode/s (raw
voltage to flying leads not the best idea! :)
73!
--
Mike Hagen, WA6ISP
10917 Bryant Street
Yucaipa, Ca. 92399
(909) 918-0058
PayPal ID "MotDog@..."
Mike@...
|
I put a resistor and a 12v LED into the TX line to my 30mm x 30mm fan which blows directly on the final heatsink. I wanted to drop the voltage to the LED and now I can see when I am in TX and that the fan is running. 73 Willy
On Sun, Nov 5, 2017 at 6:35 PM, Michael Hagen <motdog@...> wrote:
If 12V, maybe go to
3.3 to 4.7K.? Leds are fairly bright at a couple of ma?
Mike
On 11/5/2017 2:33 PM, Dexter N Muir
wrote:
Mike beat me to
it, and with better. Resistor first, then wire to diode/s (raw
voltage to flying leads not the best idea! :)
73!
--
Mike Hagen, WA6ISP
10917 Bryant Street
Yucaipa, Ca. 92399
(909) 918-0058
PayPal ID "MotDog@..."
Mike@...
|
Hi ben See attached pics, solder 2 wires below the K1 relay as shown, then to the Dual color LED , the centre of the LED goes to ground thru a 680 Ohms restistor. Have fun happy Bitxing 73 Pop VU2POP ?
toggle quoted message
Show quoted text
From: [email protected] [mailto:[email protected]] On Behalf Of Ben Piecora
Sent: Monday, November 06, 2017 2:51 AM
To: [email protected]
Subject: [BITX20] RX and TX LED ? Could anybody tell me a way I can pull voltage from the board for an LED on RX and then pull voltage from the board for a TX LED and turn off the RX LED?
|
Thank you VU2POP. Is the yellow wire for RX and the green wire for TX and then the 680 ohm resistor goes to ground? Is the LED 12 volts? I was planning on using a Red 3.3 volt LED to indicate TX and a green 3.3 volt LED to indicate RX
73 Ben Kd2nou?
On Mon, Nov 6, 2017 at 12:37 AM Prathap Naidu < vu2pop@...> wrote: Hi ben See attached pics, solder 2 wires below the K1 relay as shown, then to the Dual color LED , the centre of the LED goes to ground thru a 680 Ohms restistor. Have fun happy Bitxing 73 Pop VU2POP ? From: [email protected] [mailto:[email protected]] On Behalf Of Ben Piecora
Sent: Monday, November 06, 2017 2:51 AM
To: [email protected]
Subject: [BITX20] RX and TX LED ? Could anybody tell me a way I can pull voltage from the board for an LED on RX and then pull voltage from the board for a TX LED and turn off the RX LED?
|
You can use a dual color LED with 3 leads, centre is common gnd. I have used a standard 3mm LED , you can also use 5 mm if you need, but the 3 mm is quite Ok The 680 ohms is the dropping and current limit resistor, I have tapped the 2 wires from the K1 relay which alternates the +12V between Rx and Tx 73 Pop VU2POP ?
toggle quoted message
Show quoted text
From: [email protected] [mailto:[email protected]] On Behalf Of Ben Piecora
Sent: Monday, November 06, 2017 11:11 AM
To: [email protected]
Subject: Re: [BITX20] RX and TX LED ? Thank you VU2POP. Is the yellow wire for RX and the green wire for TX and then the 680 ohm resistor goes to ground? Is the LED 12 volts? I was planning on using a Red 3.3 volt LED to indicate TX and a green 3.3 volt LED to indicate RX ? On Mon, Nov 6, 2017 at 12:37 AM Prathap Naidu <vu2pop@...> wrote: Hi ben See attached pics, solder 2 wires below the K1 relay as shown, then to the Dual color LED , the centre of the LED goes to ground thru a 680 Ohms restistor. Have fun happy Bitxing 73 Pop VU2POP ? From: [email protected] [mailto:[email protected]] On Behalf Of Ben Piecora
Sent: Monday, November 06, 2017 2:51 AM
To: [email protected]
Subject: [BITX20] RX and TX LED ? Could anybody tell me a way I can pull voltage from the board for an LED on RX and then pull voltage from the board for a TX LED and turn off the RX LED?
|
So I can tap the wires from K1 and then use a voltage divider circuit to drop it to 3.3volts right?
Ben Kd2nou?
On Mon, Nov 6, 2017 at 12:52 AM Prathap Naidu < vu2pop@...> wrote: You can use a dual color LED with 3 leads, centre is common gnd. I have used a standard 3mm LED , you can also use 5 mm if you need, but the 3 mm is quite Ok The 680 ohms is the dropping and current limit resistor, I have tapped the 2 wires from the K1 relay which alternates the +12V between Rx and Tx 73 Pop VU2POP ? From: [email protected] [mailto:[email protected]] On Behalf Of Ben Piecora
Sent: Monday, November 06, 2017 11:11 AM
To: [email protected]
Subject: Re: [BITX20] RX and TX LED ? Thank you VU2POP. Is the yellow wire for RX and the green wire for TX and then the 680 ohm resistor goes to ground? Is the LED 12 volts? I was planning on using a Red 3.3 volt LED to indicate TX and a green 3.3 volt LED to indicate RX ? On Mon, Nov 6, 2017 at 12:37 AM Prathap Naidu <vu2pop@...> wrote: Hi ben See attached pics, solder 2 wires below the K1 relay as shown, then to the Dual color LED , the centre of the LED goes to ground thru a 680 Ohms restistor. Have fun happy Bitxing 73 Pop VU2POP ? From: [email protected] [mailto:[email protected]] On Behalf Of Ben Piecora
Sent: Monday, November 06, 2017 2:51 AM
To: [email protected]
Subject: [BITX20] RX and TX LED ? Could anybody tell me a way I can pull voltage from the board for an LED on RX and then pull voltage from the board for a TX LED and turn off the RX LED?
|
Complete basic electrics, Ben. An LED is a *current-driven* device. You can use *any* Voltage to feed it, so long as you limit the *Current*. You do this with a resistor. Here you use basic arithmetic and Ohm's law. Calculate the required resistance:? = Voltage / Current. Voltage is that supplied minus the LED's natural 'forward' (conducting / 'lit') voltage (typically that's around 1.3 Volts). So, given 12V supply and current around 10 milliAmps (a good starting point, most will give light at 2 or 3 mA and start burning out around 50mA - High-insensity types vary of course - look up the data sheets), then R = (12-1.3 / .010) which ends up around 1 or 1.2k (1000 or 1200) ohms. If only one is to be lit at a time, (RX or TX) they can share the resistor (the 'bi-color' type, or two devices). If they are to be individually lit and can be both lit, (PWR and TX) then each needs its own resistor.
73...
Dex, ZL2DEX
|
Using 680 ohms will
really make the LED bright.? I = (12V - 3.3V ) / 680.? Most
work real nice on just a few ma.? 2.2K should give nearly 5
ma.? What folks are saying is an LED is not "operated" or
"biased" with voltage.? You put a current thru them, and the
voltage is just a result.? You get what you get!
The current limit
resistor is picked for how bight you desire it to be.?? The
3.3V spec will be the approximate voltage drop at a given
current.
If you were running on
a battery, you might try only 1 or 2 ma.
Just a thought, most
take 20 ma. OK.? For an experiment, try 10K and then 1K??
Mike, WA6ISP
On 11/5/2017 9:52 PM, Prathap Naidu
wrote:
You
can use a dual color LED with 3 leads, centre is common gnd.
I
have used a standard 3mm LED , you can also use 5 mm if you
need, but the 3 mm is quite Ok
The
680 ohms is the dropping and current limit resistor, I have
tapped the 2 wires from the K1 relay which alternates the
+12V between Rx and Tx
73
Pop
VU2POP
?
From:
[email protected] [mailto:[email protected]] On Behalf Of
Ben Piecora
Sent: Monday, November 06, 2017 11:11 AM
To: [email protected]
Subject: Re: [BITX20] RX and TX LED
?
Thank you VU2POP. Is the yellow wire
for RX and the green wire for TX and then the 680 ohm
resistor goes to ground? Is the LED 12 volts? I was
planning on using a Red 3.3 volt LED to indicate TX and a
green 3.3 volt LED to indicate RX
?
On Mon, Nov 6, 2017 at 12:37 AM
Prathap Naidu <vu2pop@...> wrote:
Hi
ben
See
attached pics, solder 2 wires below the K1 relay
as shown, then to the Dual color LED , the centre
of the LED goes to ground thru a 680 Ohms
restistor.
Have
fun
happy
Bitxing
73
Pop
VU2POP
?
From:
[email protected]
[mailto:[email protected]]
On Behalf Of Ben Piecora
Sent: Monday, November 06, 2017 2:51 AM
To: [email protected]
Subject: [BITX20] RX and TX LED
?
Could
anybody tell me a way I can pull voltage from the
board for an LED on RX and then pull voltage from
the board for a TX LED and turn off the RX LED?
--
Mike Hagen, WA6ISP
10917 Bryant Street
Yucaipa, Ca. 92399
(909) 918-0058
PayPal ID "MotDog@..."
Mike@...
|
just for indication.
?at 12V you better use 4K7 regards ?sarma ?vu3zmv
On Mon, Nov 6, 2017 at 1:42 PM, Michael Hagen <motdog@...> wrote:
Using 680 ohms will
really make the LED bright.? I = (12V - 3.3V ) / 680.? Most
work real nice on just a few ma.? 2.2K should give nearly 5
ma.? What folks are saying is an LED is not "operated" or
"biased" with voltage.? You put a current thru them, and the
voltage is just a result.? You get what you get!
The current limit
resistor is picked for how bight you desire it to be.?? The
3.3V spec will be the approximate voltage drop at a given
current.
If you were running on
a battery, you might try only 1 or 2 ma.
Just a thought, most
take 20 ma. OK.? For an experiment, try 10K and then 1K??
Mike, WA6ISP
On 11/5/2017 9:52 PM, Prathap Naidu
wrote:
You
can use a dual color LED with 3 leads, centre is common gnd.
I
have used a standard 3mm LED , you can also use 5 mm if you
need, but the 3 mm is quite Ok
The
680 ohms is the dropping and current limit resistor, I have
tapped the 2 wires from the K1 relay which alternates the
+12V between Rx and Tx
73
Pop
VU2POP
?
From:
[email protected] [mailto:[email protected]] On Behalf Of
Ben Piecora
Sent: Monday, November 06, 2017 11:11 AM
To: [email protected]
Subject: Re: [BITX20] RX and TX LED
?
Thank you VU2POP. Is the yellow wire
for RX and the green wire for TX and then the 680 ohm
resistor goes to ground? Is the LED 12 volts? I was
planning on using a Red 3.3 volt LED to indicate TX and a
green 3.3 volt LED to indicate RX
?
On Mon, Nov 6, 2017 at 12:37 AM
Prathap Naidu <vu2pop@...> wrote:
Hi
ben
See
attached pics, solder 2 wires below the K1 relay
as shown, then to the Dual color LED , the centre
of the LED goes to ground thru a 680 Ohms
restistor.
Have
fun
happy
Bitxing
73
Pop
VU2POP
?
From:
[email protected]
[mailto:[email protected]]
On Behalf Of Ben Piecora
Sent: Monday, November 06, 2017 2:51 AM
To: [email protected]
Subject: [BITX20] RX and TX LED
?
Could
anybody tell me a way I can pull voltage from the
board for an LED on RX and then pull voltage from
the board for a TX LED and turn off the RX LED?
--
Mike Hagen, WA6ISP
10917 Bryant Street
Yucaipa, Ca. 92399
(909) 918-0058
PayPal ID "MotDog@..."
Mike@...
|
toggle quoted message
Show quoted text
On Mon, Nov 6, 2017 at 1:55 PM, Mvs Sarma <mvssarma@...> wrote: just for indication.
?at 12V you better use 4K7 regards ?sarma ?vu3zmv
-- Md Sofiullah
Assist. Manager
Pulse e Technologies Pvt. Ltd,
222, Phase-IV, Udyog Vihar,
Gurgaon-122015, Haryana
Cell: +91 9811842473
???????? +91 9654698929
|
My rule, for 12v I will use a 12K resistor for LEDs.
Considering todays LEDs brightness I must increase that value.
At 06-11-2017, you wrote:
toggle quoted message
Show quoted text
Using 680 ohms will really make the LED
bright.?? I = (12V - 3.3V ) / 680.?? Most work real nice on
just a few ma.?? 2.2K should give nearly 5 ma.?? What folks are
saying is an LED is not "operated" or "biased" with
voltage.?? You put a current thru them, and the voltage is just a
result.?? You get what you get!
The current limit resistor is picked
for how bight you desire it to be.? ?? The 3.3V spec will be the
approximate voltage drop at a given current.
If you were running on a battery, you
might try only 1 or 2 ma.
Just a thought, most take 20 ma.
OK.?? For an experiment, try 10K and then 1K???
Mike, WA6ISP
|
Also, the voltage drop across led changes depending on current.
?we cant take 3.3V as only white led has that voltage. As I did not read earlier posts, i really don't kmnow whether the om wants to use white led !!! ? sarma ?vu3zmv
On Mon, Nov 6, 2017 at 8:05 PM, Raj vu2zap <rajendrakumargg@...> wrote:
My rule, for 12v I will use a 12K resistor for LEDs.
Considering todays LEDs brightness I must increase that value.
At 06-11-2017, you wrote:
Using 680 ohms will really make the LED
bright.?? I = (12V - 3.3V ) / 680.?? Most work real nice on
just a few ma.?? 2.2K should give nearly 5 ma.?? What folks are
saying is an LED is not "operated" or "biased" with
voltage.?? You put a current thru them, and the voltage is just a
result.?? You get what you get!
The current limit resistor is picked
for how bight you desire it to be.? ?? The 3.3V spec will be the
approximate voltage drop at a given current.
If you were running on a battery, you
might try only 1 or 2 ma.
Just a thought, most take 20 ma.
OK.?? For an experiment, try 10K and then 1K???
Mike, WA6ISP
|
Willy
Raj vu2zap