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I buy 1K and 10K by the hundreds.? So that's what it gets.? Buy the way, Raj is correct.? One or 2 ma on the newer LEDs is usually bright enough.? I go 1K on 5V and 10K on 12V for some reason.

I have that diode on all my RaduinoX boards.? The other thing, I have left the 12V on my test fixture on many times while programming with the USB (by Mistake).? I have been Lucky.?? I? know the

My rule, for 12v I will use a 12K resistor for LEDs. Considering todays LEDs brightness I must increase that value.

I did that on an old (1.09) Allard Version.? I made a tuning function with the same name as he has. I can switch back and forth with the conditional assembly. It works but I don't get any of the

Allard :? The only way I could see that you could cram in support for an encoder for tuning would be via conditional compilation.? i.e. something like :? #if defined (ENCODER_TUNING) ? ?// code

I posted this question to another forum and didn't get much support for the idea, so I figure I'll ask here: "I'd like to get involved with some of the OTA groups -- Michigan's three year Parks On the

Folks, This morning I was working on a bitx with raduino. While connected to the PC for uploading a sketch I noticed the board was still receiving a station albeit at a lower volume. Then it occurred

2K2 for Red LED

Hi, I discovered a bug that the carrier burst is still not properly suppressed in CW-SPLIT mode. Normal (non-SPLIT) mode works OK. I'll correct that soon. 73 Allard PE1NWL

Yes it would. One of?my most important design criteria for the Raduino code is that it shall always work, even on a standard unmodified BitX40 (which uses?Ashhar Farhan's?tuning concept based on a

Hi, I think, You need to solder and test pcb's for transceivers, before publish them. 73!LZ1DPN

just for indication. at 12V you better use 4K7 regards sarma vu3zmv regards Sarma

Using 680 ohms will really make the LED bright.? I = (12V - 3.3V ) / 680.? Most work real nice on just a few ma.? 2.2K should give nearly 5 ma.? What folks are saying is an LED is not "operated"

Complete basic electrics, Ben. An LED is a *current-driven* device. You can use *any* Voltage to feed it, so long as you limit the *Current*. You do this with a resistor. Here you use basic arithmetic

So I can tap the wires from K1 and then use a voltage divider circuit to drop it to 3.3volts right? Ben Kd2nou

You can use a dual color LED with 3 leads, centre is common gnd. I have used a standard 3mm LED , you can also use 5 mm if you need, but the 3 mm is quite Ok The 680 ohms is the dropping and current

Thank you VU2POP. Is the yellow wire for RX and the green wire for TX and then the 680 ohm resistor goes to ground? Is the LED 12 volts? I was planning on using a Red 3.3 volt LED to indicate TX and a

Hi ben See attached pics, solder 2 wires below the K1 relay as shown, then to the Dual color LED , the centre of the LED goes to ground thru a 680 Ohms restistor. Have fun happy Bitxing 73 Pop VU2POP

I tuned in late, but there was too much noise. I was using the FT-101 and the noise floor was about an S7 or S8. Vince. -- Michigan VHF Corp. http://www.nobucks.net/ http://www.CDupe.com/

Only made one contact. NX2U, Michael, in TN. Heard a few, very light, but couldn't make out the details. Kevin - NC KN4AAG